Use the graph to identify the slope and y-intercept. Can you help me identify them?.
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Answer:
(- , 0 )
Step-by-step explanation:
to find where the line crosses the x- axis, let y = 0 in the equation and solve for x
5x - 2(0) + 1 = 0
5x - 0 + 1 = 0
5x + 1 = 0 ( subtract 1 from both sides )
5x = - 1 ( divide both sides by 5 )
x = -
the line crosses the x- axis at (- , 0 ) or ( - 0.2, 0 )
You want to isolate the x-term from the constant term, so you can subtract x/3 and add 10. This gives you
... 4/9x -10 -x/3 +10 > x/3 -12 -x/3 +10
... 1/9x > -2 . . . . . . collect terms
Now, you can multiply by 9 to see the condition on x.
... 9(1/9x) > -2(9)
... x > -18
On the x-y plane, the graph of this will be a dashed line at x=-18, and the half-plane to the right of that line will be shaded.
On a number line, there will be an open circle at x=-18, and the number line to the right of that circle will be marked (bold, colored, shaded, whatever).
