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Kipish [7]
3 years ago
10

Use the graph to identify the slope and y-intercept. Can you help me identify them?.​

Mathematics
1 answer:
Crazy boy [7]3 years ago
5 0

Answer:

y intercept is (0,4) and slope is -2

Step-by-step explanation:

y intercept is (0,4) you can see where it intercepts.

The slope is rise/run so 4/-2 so -2

You might be interested in
Drone INC. owns four 3D printers (D1, D2, D3, D4) that print all their Drone parts. Sometimes errors in printing occur. We know
USPshnik [31]

Answer:

Step-by-step explanation:

Hello!

There are 4 3D printers available to print drone parts, then be "Di" the event that the printer i printed the drone part (∀ i= 1,2,3,4), and the probability of a randomly selected par being print by one of them is:

D1 ⇒ P(D1)= 0.15

D2 ⇒ P(D2)= 0.25

D3 ⇒ P(D3)= 0.40

D4 ⇒ P(D4)= 0.20

Additionally, there is a chance that these printers will print defective parts. Be "Ei" represent the error rate of each print (∀ i= 1,2,3,4) then:

P(E1)= 0.01

P(E2)= 0.02

P(E3)= 0.01

P(E4)= 0.02

Ei is then the event that "the piece was printed by Di" and "the piece is defective".

You need to determine the probability of randomly selecting a defective part printed by each one of these printers, i.e. you need to find the probability of the part being printed by the i printer given that is defective, symbolically: P(DiIE)

Where "E" represents the event "the piece is defective" and its probability represents the total error rate of the production line:

P(E)= P(E1)+P(E2)+P(E3)+P(E4)= 0.01+0.02+0.01+0.02= 0.06

This is a conditional probability and you can calculate it as:

P(A/B)= \frac{P(AnB)}{P(B)}

To reach the asked probability, first, you need to calculate the probability of the intersection between the two events, that is, the probability of the piece being printed by the Di printer and being defective Ei.

P(D1∩E)= P(E1)= 0.01

P(D2∩E)= P(E2)= 0.02

P(D3∩E)= P(E3)= 0.01

P(D4∩E)= P(E4)= 0.02

Now you can calculate the probability of the piece bein printed by each printer given that it is defective:

P(D1/E)= \frac{P(E1)}{P(E)} = \frac{0.01}{0.06}= 0.17

P(D2/E)= \frac{P(E2)}{P(E)} = \frac{0.02}{0.06}= 0.33

P(D3/E)= \frac{P(E3)}{P(E)} = \frac{0.01}{0.06}= 0.17

P(D4/E)= \frac{P(E4)}{P(E)} = \frac{0.02}{0.06}= 0.33

P(D2)= 0.25 and P(D2/E)= 0.33 ⇒ The prior probability of D2 is smaller than the posterior probability.

The fact that P(D2) ≠ P(D2/E) means that both events are nor independent and the occurrence of the piece bein defective modifies the probability of it being printed by the second printer (D2)

I hope this helps!

8 0
3 years ago
In a reliability test there is a 42% probability that a computer chip survives more than 500 temperature cycles. If a computer c
Strike441 [17]

Answer:

The probability is P(B' n A ' ) =  16%

Step-by-step explanation:

From the  question we are told that  

     A  is the event that  the chip was "made by company A"

      B is  the event that a chip "survives 500 temperature cycles"

    The probability that a computer chip survives more than 500 temperature cycles is

     P(B) = 42% = 0.42

 The  probability that does not survive more than 500 temperature cycles and  it was manufactured by company A is  P(A | B' ) =  0.73

The probability that the  computer chip is not manufactured by company A and does not survive more than 500 temperature cycles is mathematically evaluated as

      P(B' n A ' ) =  P (B' | A' ) P(B ')

Where B' \ and \   A' are a A and B complements and  | represented AND operator  

  So  

        P(B' n A ' ) = [1 -  P (B' | A )] [1 - P(B )]

substituting values

         P(B' n A ' ) = [1 -  0.73] [1 - 0.42 ]

        P(B' n A ' ) = (0.27 )(0.58)

        P(B' n A ' ) =0.16

        P(B' n A ' ) =  16%

7 0
3 years ago
The answer would be 7/8 right?
trasher [3.6K]
Yes, it would be what you have written
6 0
3 years ago
90° clockwise rotation<br> Help please
maria [59]

Answer:

E' (-2,5)

F' (-3,1)

G' (-2,-1)

H' (0,3)

Step-by-step explanation:

The rule for 90 degree clockwise rotation is (h,k) -> (k,-h). This means flip the x-value's sign and then switch x and y's position. For example E (-5,-2), first flip x's sign (5,-2) and then switch x and y's places (-2,5).

4 0
3 years ago
Helppppppppppppppppppppppppppppppppppppppppppppp
aleksley [76]

Answer:

with what?

Step-by-step explanation:

5 0
2 years ago
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