Consider the points Q(23, 48) and R(7, 62). What is the component form of Vector Q R?

Mathematics

2 answers:

aev [14]2 years ago

8 0

Answer:

The correct option is;

LeftAngleBracket negative 16, 14 RightAngleBracket which is $\left \langle -16, 14 \right \rangle$

Step-by-step explanation:

The given coordinates of the points are;

The starting point, Q(23, 48) and the final point, R(7, 62)

Therefore, we have;

The x component = The x-value of R - The x-value of R = 7 - 23 = -16

The y component = The y-value of R - The y-value of R = 62 - 48 = 14

Therefore, the component form of the vector QR = $\left \langle -16, 14 \right \rangle$

Alika [10]2 years ago

4 0

Answer:

B on Edg.

Step-by-step explanation:

Yay

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Question 2

svetoff [14.1K]

Answer:

A: 37/41

Step-by-step explanation:

<u>We can observe that:</u>

The difference of the second and third numbers is equal to 17
The difference of the first and fourth numbers is equal to 13

<u>Therefore the missing pair will be:</u>

20+17 = 37 and 28 + 13 = 41

Correct choice is A

3 0

2 years ago

A Geometric series has a first term of 4 and a common ratio of 6. what formula is equivalent to the partial sum of the first n t

IRISSAK [1]

$\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=4\\
r=6
\end{cases}
\\\\\\
S_n=4\left( \cfrac{1-6^n}{1-6} \right)\implies S_n=4\left( \cfrac{1-6^n}{-5} \right)$