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3 years ago

7

PLZ HELP!! A die is rolled. What is the probability of rolling a 2 or a 6? >>Also, is this an mutually exclusive or inclus

ive event? >>Also please show your work Thanks!

2 answers:

Nutka1998 [239]3 years ago

8 0

The probability would be 2/6, or 1/3 if you were to reduce the fraction.

erastovalidia [21]3 years ago

4 0

The probability would be that there are 6 sides on a die. So the probability is 2 out of 6 or you can simplify to 1 out of 3.

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3 years ago

The first two terms in an arithmetic progression are -2 and 5. The last term in the progression is the only number in the progre

Rudik [331]

Given:

The first two terms in an arithmetic progression are -2 and 5.

The last term in the progression is the only number in the progression that is greater than 200.

To find:

The sum of all the terms in the progression.

Solution:

We have,

First term : $a=-2$

Common difference : $d = 5 - (-2)$

$= 5 + 2$

$= 7$

nth term of an A.P. is

$a_n=a+(n-1)d$

where, a is first term and d is common difference.

$a_n=-2+(n-1)(7)$

According to the equation, $a_n>200$ .

$-2+(n-1)(7)>200$

$(n-1)(7)>200+2$

$(n-1)(7)>202$

Divide both sides by 7.

$(n-1)>28.857$

Add 1 on both sides.

$n>29.857$

So, least possible integer value is 30. It means, A.P. has 30 term.

Sum of n terms of an A.P. is

$S_n=\dfrac{n}{2}[2a+(n-1)d]$

Substituting n=30, a=-2 and d=7, we get

$S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]$

$S_{30}=15[-4+(29)7]$

$S_{30}=15[-4+203]$

$S_{30}=15(199)$

$S_{30}=2985$

Therefore, the sum of all the terms in the progression is 2985.

6 0

3 years ago