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3 years ago

Bx^(2)+2b^(2)-b^(3)-2x^(2)

Mathematics

1 answer:

8090 [49]3 years ago

8 0

Answer:

(b+x)(−b+x)(b−2)

Step-by-step explanation:

Factor bx2 + 2b2 − b3 − 2x2 − b3 + bx2 + 2b2 − 2x2 = (b+x)(−b+x)(b−2)

hope this helps! :)

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Solve for x 2x^2 = 128 Answers -6 and 6 -8 and 8 -32 and 32 -64 and 64

uysha [10]

Divide both sides by 2

x^2 = 128/2

Simplify 128/2 to 64

x^2 = 64

Take the square root of both sides;

x = √64

Since 8 * 8 = 64, the square root of 64 is 8

x = -8 and 8

Answer: B -8 and 8

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3 years ago

What ratio would you use to determine how many seconds are in a minute?

meriva

60:1

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3 years ago

The temperature today was 10 degrees colder than twice yesterday's temperature, t.

Aneli [31]

Answer: Today's temperature : 2t -10

Step-by-step explanation:

Hi, to write the expression of the statement given we have to analyze each phrase:

Twice yesterday's temperature, t. If t is yesterday’s temperature, twice that temperature equals 2t.

The temperature today was 10 degrees colder than: It means that we have to subtract 10 degrees :(-10)

Mathematically speaking:

Today's temperature : 2t -10

where t = yesterday's temperature

Feel free to ask for more if needed or if you did not understand something.

5 0

4 years ago

Two birds are sitting on the ground below their nest. Bird A is between the nest and Bird B. The angle of elevation from Bird A

ruslelena [56]

Answer:

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Step-by-step explanation:

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3 years ago

Find the length of the curve y = integral from 1 to x of sqrt(t^3-1)

Arlecino [84]

$y=\displaystyle\int_1^x\sqrt{t^3-1}\,\mathrm dt$

By the fundamental theorem of calculus,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm d}{\mathrm dx}\displaystyle\int_1^x\sqrt{t^3-1}\,\mathrm dt=\sqrt{x^3-1}$

Now the arc length over an arbitrary interval $(a,b)$ is

$\displaystyle\int_a^b\sqrt{1+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx=\int_a^b\sqrt{1+x^3-1}\,\mathrm dx=\int_a^bx^{3/2}\,\mathrm dx$

But before we compute the integral, first we need to make sure the integrand exists over it. $x^{3/2}$ is undefined if $x$ , so we assume $a\ge0$ and for convenience that $a$ . Then

$\displaystyle\int_a^bx^{3/2}\,\mathrm dx=\frac25x^{5/2}\bigg|_{x=a}^{x=b}=\frac25\left(b^{5/2}-a^{5/2}\right)$

6 0

3 years ago