Bx^(2)+2b^(2)-b^(3)-2x^(2)

Mathematics

1 answer:

8090 [49]2 years ago

8 0

Answer:

(b+x)(−b+x)(b−2)

Step-by-step explanation:

Factor bx2 + 2b2 − b3 − 2x2 − b3 + bx2 + 2b2 − 2x2 = (b+x)(−b+x)(b−2)

hope this helps! :)

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two circles are externally tangent to each other. One circle has a diameter of 62 yards and the distance between the centers of

maksim [4K]

Answer:

108 yards

Step-by-step explanation:

Let circle A be the circle with the 62 yard diameter

Let circle B be the circle whose diameter we are trying to solve for.

Externally tangent circles are circles which touch each other and share a common external tangent.
Circle A has a tangent of 62 yards and thus a radius ( half the diameter) of 31 yards.
The distance between the centers of the 2 circles is 85 yards. If you subtract the radius ( distance from the center of the circle to its circumference) of circle A then we'll only be left with the radius of circle B.
85 - 31= 54 yards which is the radius of circle B
To get the diameter: 54 x 2 = 108 yards