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Svetlanka [38]
3 years ago
15

Bx^(2)+2b^(2)-b^(3)-2x^(2)

Mathematics
1 answer:
8090 [49]3 years ago
8 0

Answer:

(b+x)(−b+x)(b−2)

Step-by-step explanation:

Factor bx2 + 2b2 − b3 − 2x2  − b3 + bx2 + 2b2 − 2x2  = (b+x)(−b+x)(b−2)

hope this helps! :)

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tim has been offered three jobs. job a paid on an annual basis with a salary of 26,700. job b pays $500 per week. job c pays &am
scZoUnD [109]

Answer:

Job C

Step-by-step explanation:

Since he's paid semi monthly,literally half a month, which is 1125$

Then full month will be 1125×2

Which is 2250

Then annually would be 2250×12=27,000

5 0
4 years ago
10. Does the mapping represent a function?
alexira [117]
The answer is b no because -8 goes into two answers
7 0
3 years ago
A factory that produces piano keys churned out 545,952 keys in 12 months. A piano requires 88 keys. How many pianos can be produ
Mariana [72]
Divide the total amount of keys produced by the amount of keys a piano requires to find the amount of pianos a factory made:

545,952 \div 88 = 6204

The factory made 6204 pianos in 12 months.

Because the question asks for the amount of pianos made for the first 3 months, we'll divide the total 12 months by the 3 months the question asks for:

12 \div 3 = 4

Now we'll divide the total amount of pianos made in 12 months by this number to find the pianos made in 3 months:

6204 \div 4 = 1551

1551 pianos were made in the first 3 months of production.
5 0
3 years ago
Read 2 more answers
Help will mark brainliest
wlad13 [49]

Answer:

c.  

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Step-by-step explanation:

7 0
3 years ago
A veterinarian collects data on the number of times race horses are raced during their careers. The veterinarian finds that the
SpyIntel [72]

Answer:

c. (12.12, 18.48)

Step-by-step explanation:

Hello!

The study variable is X: number of times a racehorse is raced during its career.

The average number is X[bar]= 15.3 and the standard deviation is S= 6.8 obtained from a sample of n=20 horses.

To estimate the population mean you need that the variable has a normal distribution, in this case, we have no information about its distribution so I'll assume that it has a normal distribution. With n=20 the most accurate statistic to use for the estimation is a Students-t for one sample, the formula for the interval is:

X[bar] ± t_{n-1;1-\alpha /2} * \frac{S}{\sqrt{20} }

t_{n-1;1-\alpha /2} = t_{19;0.975}= 2.093

[15.3 ± 2.093 * \frac{6.8}{\sqrt{20} }]

[12.12; 18.48]

Using a significance level of 95% you'd expect that the true average of times racehorses are raced during their career is included in the interval [12.12; 18.48].

I hope it helps!

8 0
4 years ago
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