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Elina [12.6K]
2 years ago
6

9. Evan's dog weighs 4 pounds. What is the weight of Evan's dog in ounces?

Mathematics
2 answers:
torisob [31]2 years ago
7 0

Evan's dog weighs 64 ounces

kap26 [50]2 years ago
3 0
His dog weighs 64 ounces
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Kanna wants to buy 6 of flowers. Each flower cost $1.30 but the bundle of 6 cost $7.50. What is the better deal for Kanna.
Nat2105 [25]

Answer: 6 for $7.50

Step-by-step explanation:

6 * 1.30 = $7.80

6 for $7.50

7 0
2 years ago
5 : 2 : 11 =.... : 6 : ....
lubasha [3.4K]
5:2:11=15:6:33
Multiply by 6/2=3
7 0
2 years ago
Gorden made 32 cookies which of the answer choices shows all the factor pairs of 32
faltersainse [42]

32 = 1 x 32, 2 x 16, or 4 x 8. Factors of 32: 1, 2, 4, 8, 16, 32

Hope I heled! :)

4 0
3 years ago
Read 2 more answers
Suppose you are paid an annual salary, plus a bonus of 20% on annual sales over $500,000. Consider the two functions f(x) = x −
melisa1 [442]

Answer:

C. g\,\circ \, f (x) =g(f(x))

Step-by-step explanation:

Let be f(x) = x-500000 the excedent on annual sales and g(x) = 0.2\cdot x the bonus factor, to determine the bonus amount a composition of f(x) is g(x) must be done. That is:

g\,\circ \, f (x) =g(f(x))

Hence, the right answer is C.

7 0
3 years ago
What is the GCF of 48m5n and 81m2n2?
Lady bird [3.3K]
To find the GCF of the two terms, continuous division must be done.
What can be used to divide both terms such that there is not a remainder?
Start small, let's take 2. It could be a GCF.
Move up higher, say 3. Yes, it can be a GCF.
To see if there might be a greater common factor, divide the constants by 3.
48/3 = 16
81/3 = 27
Upon inspection and contemplation, there is no more common factor between 16 and 27. So, 3 is the GCF.

Moving on, when it comes to variables. The variable with the least exponents is easily the GCF. For the variable m, the GCF is m2 and for n, the GCF is n.

Combining the three, we have the overall GCF = 3m2n
7 0
3 years ago
Read 2 more answers
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