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2 years ago

5⁄8 ÷ 3⁄8 =________ pls help me

Mathematics

2 answers:

rjkz [21]2 years ago

4 0

Answer:

1 $\frac{2}{3}$

Step-by-step explanation:

siniylev [52]2 years ago

3 0

Answer:

1 2/3

Step-by-step explanation:

First, you rewrite 5/8÷3/8 as a multiplication problem: 5/8*8/3. Now you simply multiply both numerators and denominators: 5x8/8x3 which equals 40/24. So your final answer will be 40/24 or 1 16/24 which equals 1 2/3.

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Evaluate v(x)=12-2x-5 when x=-2,0, and 5 . v(-2)= v(0)= v(5)=

Vaselesa [24]

Step-by-step explanation:

v(-2)= 12-2x(-2)-5

=12+4-5

=16-5

=11

v(0)= 12-2x0-5

= 12-0-5

=12-5

v(5)= 12-2x5-5

= 12-10-5

=12-5

Hope it helps 

6 0

2 years ago

Can some one answer this ?

earnstyle [38]

This is your answer

5 0

3 years ago

Which of the following is the radical expression of a to the four ninths power ?

LuckyWell [14K]

Given expression in exponential form : $a^{\frac{4}{9} }$ .

We need to convert it into radical form.

Please note: When we convert an exponential to radical form, the top number goes in the exponent of the term and bottom number of the fraction goes in the radical sign to make it nth radical.

We can apply following rule:

$(a)^{\frac{m}{n}}= \sqrt[n]{x^m}$ .

Therefore,

$a^{\frac{4}{9} }= \sqrt[9]{a^4}$ .

Therefore, correct option is : D. ninth root of a to the fourth power.

6 0

3 years ago

Which is the same as multiplying a number by two?

Pachacha [2.7K]

C adding a number to itself

5 0

3 years ago

What are the coordinates of the vertices of the rose garden after a translation two yards east and four yards south? Use the ter

melisa1 [442]

Answer:

The coordinates of the vertices of the original rose garden are A(3, 6), B(3, 3), C(4, 3), and D(4, 6).

Because the rose garden is translated 2 yards east (2 units in the positive x-direction) and 4 yards south (4 yards in the negative y-direction), add 2 units to the x-coordinates and -4 units to the y-coordinates of all the original vertices.

A(3, 6) will become A'[(3 + 2), (6 + (-4))], or A′(5, 2).

B(3, 3) will become B'[(3 + 2), (3 + (-4))], or B′(5, -1).

C(4, 3) will become C'[(4 + 2), (3 + (-4))], or C′(6, -1).

D(4, 6) will become D'[(4 + 2), (6 + (-4))], or D′(6, 2).

8 0

3 years ago