Answer:
PQ
SR
PR
Step-by-step explanation:
they are all going down while the others rise
Median: 23.5
12 and 35 are in the middle so you add them and divide by 2, leaving you
23.5 as your median.
Mean: 41.3
Add all numbers together and divide the sum by the number of numbers added. So all numbers added together equals 413. Divide by ten the nuber of numbers added. 413/10 equals 41.3.
Mode: 99
The number that appears most often. In this case, 99 would be the mode.
Range: 98
The lowest number subtracted from the highest number. 99-1 equals 98.
IQR: 84.75
Hope this helped! :)
Yeah Imao you usually do these type of questions on a calculator but I've tried writing it on a calculator and it keeps on saying "error" so I'm gonna guess the question is wrong or sth
but if you type out the question without the bracket before the 12 you'll get 6.63
anyway hope this helps- have a good day bro cya)
Sum of three consecutive odd integers = 
The values of the three integers.
Let us assume the three consecutive odd integers to be 
, 
and 
.
As per the condition, we have
Now, collect the like terms.
Therefore, the three consecutive odd integers whose sum is are 
, 
and 
respectively.
⇢ L. H. S. = R. H. S.
Answer:
The probability is 0.31
Step-by-step explanation:
In this question, we are tasked with calculating the probability that a random plumber called at Denver will charge an amount greater than $86 given the mean and the standard deviation.
Firstly, we calculate the standard score of $86 using the mean and the standard deviation.
Mathematically;
z-score = (x-mean)/SD
where x = 86, mean = 84 and SD = 4
z-score = (86-84)/4 = 2/4 = 0.5
Hence, we want to calculate P(z ≥ 0.5)
Using standard table
P( (z ≥ 0.5) = 1 - P(z ≤ 0.5) = 1 - ( 0.19146 + 0.5) = 0.30854
To the nearest hundredth = 0.31
