Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
If one kilogram is equal to 35.274 then just multiply 1.5 by 35.274.
1.5 * 35.274 = <span>52.911</span>
Substitution method is one of the ways to solve this system.
-5x+y=4 and 4x-4y=16.
First we will divide the second equation with number 4 and get
x-y=4 => x=y+4 than we will replace x in the first equation
-5(y+4)+y=4 => -5y-20+y=4 => -4y=4+20 => -4y=24 => y=-6
x-(-6))=4 => x+6=4 => x=4-6=-2 (x,y)=(-2,-6)
Good luck!!!
Answer: 2.4
Step-by-step explanation: just divide 57 and 24 then round the answer to the nearest 10th
