Answer:
-1.64
Explanation:
Multiple Choice Answers that were not provided in the question:
a. 0.103 .
b. None of the above.
c. -4.16
d. -1.45
e. 2.86
f .-1.64
The provided data is as below:
Student 1 Student 2 Student 3 Student 4 Student 5 Student 6
Pre- test 80 76 76 50 48 67
Post- test 75 86 87 60 48 68
Further Explanation:
Student 1 Student 2 Student 3 Student 4 Student 5 Student 6
Pre- test 80 76 76 50 48 67
Post- test 75 86 87 60 48 68
Pretest-Postest 5 -10 -11 -10 0 -1
Calculating the mean of the difference (Pretest-postest) we get d bar = -4.5
Calculating the standard deviation of the difference (Pretest-postest) we get sd= 6.716.
Since sample score is under 30 and population standard deviation is unknown, we will use a tscore to find the standardized test statistic
t = dbar/(sd/√n) = -4.5/(6.716√6) = -1.642 ≈ -1.64
The test statistic is -1.64.
