Question

Please help me ASAP I WILL GIVE U BRAINLIEST!

Answer 1

Answer:

$\sqrt{13}$

Step-by-step explanation:

Given a vector < x, y > then its magnitude is

$\sqrt{x^2+y^2}$

Given the directed line segment

P (0, 0 ) → Q (3, 2 ) then

PQ = q - p = (3, 2 ) - (0, 0 ) = < 3 - 0, 2 - 0 > = < 3 , 2 >

| PQ | = $\sqrt{3^2+2^2}$ = $\sqrt{9+4}$ = $\sqrt{13}$