Well there are no choices listed so it's going to be hard to say which; we'll write an expression for all of them and then give a few instances.
A parabola with a minimum forms a CUP, concave-up positive, meaning the coefficient a on x² must be positive, a>0.
The general form with vertex (p,q) is
y = a(x-p)² + q
So for us, all our parabolas are of the form
y = a(x- -3)² + 9
y = a(x² + 6x + 9) + 9
y = ax² + 6ax + 9(a+1)
That's the general form for a parabola with vertex (-3,9); a>0 assure the parabola has a minimum at the vertex.
Some instances:
a=1 gives
Answer: y = x²+6x+18
a=4 gives
y = 4x² + 24x + 45
Other positive <em>a</em>s give other possible answers; without the choices it's impossible to know which one they're seeking.