Answer:
approximately 0.2 days
Step-by-step explanation:
Flow is defined as:
Q = V/t
where Q is flow, V is volume, and t is time
Let's call Vr to the volume of the reservoir, then for the first channel:
Q1 = Vr/t1
Replacing with t1 = 1/3 of day:
Q1 = Vr/(1/3) = 3*Vr
Similarly, or the other channels:
Q2 = Vr/1 = Vr
Q3 = Vr/(2 1/2) = 2/5*Vr
Q4 = Vr/3
Q5 = Vr/5
When all channels are open, the time needed to fill the reservoir is:
Vr = t*(Q1 + Q2 + Q3+ Q4 + Q5)
Replacing with the previous equivalences:
Vr = t*(3*Vr + Vr + 2/5*Vr+ Vr/3 + Vr/5)
Vr = t*4.93*Vr
1/4.93 = t
0.2 = t
Answer:
A. 10,000
B. 1,000,000
C. 10,000,000,000
D. 1,000,000,000,000
Step-by-step explanation:
10,000/ 10∧4 = 1
1,000,000/ 10∧6 = 1
10,000,000,000/ 10∧10 = 1
1,000,000,000,000/ 10∧12 = 1
Hope this helps! Good luck!
Answer:
If you mean:
x² = 10
√x² = √10
x = √10
if you meant:
2x = 10
2x/2 = 10/2
x = 10/2
x = 5
hope this helps
If you mean x^2 then there would be no answer after all, 3^2= 9 and 4^2= 16 so
If you mean 2x then the answer would be 5
Step-by-step explanation:
:0
Answer:
Option C is correct answer.
Step-by-step explanation:
We need to draw the graph of piece wise function
![f(x)\[ \begin{cases} -2-x & if\:x\leq 1 \\ -3+2x & if\: x>1 \end{cases}\]](https://tex.z-dn.net/?f=f%28x%29%5C%5B%20%5Cbegin%7Bcases%7D%20%20%20%20%20%20%20-2-x%20%26%20if%5C%3Ax%5Cleq%201%20%5C%5C%20%20%20%20%20%20-3%2B2x%20%26%20if%5C%3A%20x%3E1%20%20%20%5Cend%7Bcases%7D%5C%5D)
So, for drawing the graph, we will find values of f(x) for both the given equations.
First finding f(x) for 
The value of x must be less than or equal 1
x f(x)
1 -3
0 -2
-1 -1
-2 0
-3 1
-4 2
The graph will start from closed circle because x ≤ 1
Now, finding values of f(x) for 
The value of x must be greater than 1
x f(x)
2 1
3 3
4 5
5 7
The graph will start from open circle because x> 1
Now, plotting these numbers we will get graph of Option C.
Option C is correct answer.
