If the equation is passing trough the origin, it will be passing trough the point (0,0). We now for our problem that the equations is also passing trough the point (-4,3). So, our line is passing trough the points (0,0) and (-4,3). To write the equation in slope-intercept form, first, we need to find its slope . To do that we are going to use the slope formula: .
From our two points we can infer that , , , . Lets replace those values in the slope formula:
Now that we have our slope, we can use the slope-intercept formula:
We can conclude that the equation of the line passing trough the points (0,0) and (-4,3) is .
Area of the composite shape = 292 yd²
Solution:
The shape is splitted into two rectangles.
The reference image of the answer is attached below.
Length of the top rectangle = 21 yd
Width of the top rectangle = 29 yd – 22 yd = 7 yd
Length of the side rectangle = 29 yd
Width of the side rectangle = 26 yd – 21 yd = 5 yd
Area of the figure = Area of the top rectangle + Area of the side rectangle
= (length × width) + (length × width)
= (21 × 7) + (29 × 5)
= 147 + 145
= 292
Area of the composite shape = 292 yd²
Answer:
$2
Step-by-step explanation:
To use a percent you must change it to a decimal.
8% is .08
To find 8% of 25, we use multiplication.
.08 × 25
= 2
In case you cannot use a calculator or you want to be very quick about this, or just do a simple check... you can actually reverse the number (money, amount, etc) and the percent.
25% of 8 is not bad for doing mental math. 25% is a quarter, or 1/4 of 8 which again is 2.
The area of a square increases by a factor 2n when its perimeter increases by a factor of n
<h3>How to determine the perimeter and area of each square?</h3>
Start by calculating the side length of each square
From the diagram, we have the following side lengths in ascending order
Square 1 = 2
Square 2 = 4
Square 3 = 8
<u>The perimeter</u>
This is calculated as:
P = 4 * Side length
So, we have:
Perimeter Square 1 = 4 * 2 = 8
Perimeter Square 2 = 4 * 4 = 16
Perimeter Square 3 = 4 * 8 = 32
Hence, the perimeters of the squares are 8, 16 and 32
<u>The area</u>
This is calculated as:
A = Side length^2
So, we have:
Area Square 1 = 2^2 = 4
Area Square 2 = 4^2 = 16
Area Square 3 = 8^2 = 64
Hence, the areas of the squares are 4, 16 and 64
<h3>What happens to the area of a square when its perimeter increases by a factor of n?</h3>
Using the computations in (a), the area of a square increases by a factor 2n when its perimeter increases by a factor of n
Read more about area and perimeter at:
brainly.com/question/24571594
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