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3 years ago

9

What are the multiples of 14?

2 answers:

Mrrafil [7]3 years ago

7 0

14,28,42,56,70,84,98,112,126,140,154,168,182,196,210,224,238,252,266,280,294,308,

Is that enough?

Tems11 [23]3 years ago

4 0

14,28,42,56,70,84,98,112,126,140,154,168,182,196,210,224,238,252,266,280,294,308,322,336,350,364,378,392,406,420,434,448 these are some but there are more

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7(x-2)=28 Can somebody help me and show the steps?

olya-2409 [2.1K]

Since the 7 is in front of the parentheses you must multiply it by everything inside the parentheses. 7 times X is 7X and 7 times -2 is -14. Then you need to make the X be by itself on one side, to do that you have to add 14 to -14 to make it disappear, and also add 14 to the other side, to 28. Then you divide both sides by 7 to make X be by itself.

7(x-2)=28
7X-14=28
7x=42
X=6

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3 years ago

look at the angles for all regular polygons.as the number of sides increases did the measures of the angles increase or decrease

SCORPION-xisa [38]

Typically when a polygon has more sides, the angles get smaller.

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4 years ago

Keri is simplifying 5·10^−3.

11111nata11111 [884]

Answer:

1. D

2. A

Step-by-step explanation:

Q1. Kerry is simplifying $5\cdot 10^{-3}$

By the definition of negative powers,

$a^{-n}=\dfrac{1}{a^n}$

Hence,

$10^{-3}=\dfrac{1}{10^3}$

So, the first step in simplifying the expression is

$5\cdot 10^{-3}=5\cdot \dfrac{1}{10^3}$

Q2. Given the expression

$\dfrac{8}{10^{-2}}$

First, use the definition of negative powers:

$10^{-2}=\dfrac{1}{10^2}$

Thus,

$\dfrac{8}{10^-2}=\dfrac{8}{\frac{1}{10^2}}=8\cdot 10^2=8\cdot 100=800$

8 0

3 years ago

The linear equation has 5(x + 2) = 5x + 2 A) no solution. B) one solution. C) two solutions. D) infinitely many solutions.

erik [133]

I would say C!!!!!!!!!

4 0

3 years ago

Read 2 more answers

In which quadrant is (-1/2, -1.8)?

andrey2020 [161]

X = -1/2 (negative)
y = - 1.8 (negative)

so It's in Quadrant 3

5 0

3 years ago