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2 years ago

What are the multiples of 14?

Mathematics

2 answers:

Mrrafil [7]2 years ago

7 0

14,28,42,56,70,84,98,112,126,140,154,168,182,196,210,224,238,252,266,280,294,308,

Is that enough?

Tems11 [23]2 years ago

4 0

14,28,42,56,70,84,98,112,126,140,154,168,182,196,210,224,238,252,266,280,294,308,322,336,350,364,378,392,406,420,434,448 these are some but there are more

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(49^3)^1/8 <br> What is the value of the expression?

alexgriva [62]

49^3/8
decimal form: 4.30351707

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3 years ago

1) What is the area of the rectangle?<br> 4 yd<br> 7yd

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1 year ago

Read 2 more answers

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

blondinia [14]

Substitute y = 1/5 x + 1 into x + 5y = -15

x + 5y = -15

x + 5(1/5 x + 1) = -15

x + x + 5 = -15

2x = -20

x = -10

Plug in x = -10 into y = 1/5 x + 1

y = 1/5 (-10) + 1

y = -2 + 1

y = -1

(-10 , -1)

Answer is the last one

(-10 , -1)

3 0

2 years ago

Find the quotient simplify 2/ divided by 8/10

Tanya [424]

Answer:

Step-by-step explanation:

Use KCF method

Keep the first.

Change division to multiplication.

Flip the second number.

2 ÷ $\frac{8}{10}$

$=2 * \dfrac{10}{8}\\\\=\dfrac{10}{4}=\dfrac{5}{2}\\\\=2\dfrac{1}{2}$

6 0

2 years ago

Find an equation of the normal line to the parabola y=x^2-5x+4 that is parallel to the line x-3y=5

Step2247 [10]

The equation of the normal line is parallel to x - 3y = 5
3y = x - 5
y = 1/3x - 5/3
The normal line has a slope of 1/3 and the slope of the tangent line is -3
Let the point at which the normal line passes the parabola be (x1, y1), then
f'(x1) = 2x - 5 = -3
2x = -3 + 5 = 2
x = 2/2 = 1
y = (1)^2 - 5(1) + 4 = 1 - 5 + 4 = 0
Therefore, the normal line passes through point (1, 0) and has a slope of 1/3.
Therefore, required equation is y = 1/3(x - 1)
y = 1/3x - 1/3

3 0

2 years ago