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Oliga [24]
2 years ago
15

Dont guess! I will mark brainliest if its correct! Also no links!

Mathematics
2 answers:
brilliants [131]2 years ago
8 0

Answer:

I know you said no guessing, but I'm assuming it's the first one, F.

Alborosie2 years ago
6 0

Answer:

The second graph as per my best guess LOL

Step-by-step explanation:

LMK if I'm wrong please

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Click the picture that I sent you
Digiron [165]

Answer: 1211.6585 years

<u>Step-by-step explanation:</u>

The equation for exponential growth is: P=P_oe^{kt}

  • P: final population
  • P₀: initial population
  • k: rate of decay (or growth)
  • t: time

Use the half life information to find k:

\dfrac{1}{2}P_o=P_oe^{k(800)}\\\\\\\dfrac{1}{2}=e^{800k}\qquad \rightarrow \qquad \text{divided both sides by}\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=800k\qquad \rightarrow \qquad \text{applied ln to both sides}\\\\\\\dfrac{ln(\frac{1}{2})}{800}=k\qquad \rightarrow \qquad \text{divided both sides by 800}\\\\\\\large\boxed{-0.000867=k}

Next, input the information (65% decayed = 35% remaining) and the k-value to find your answer.

.35P_o=P_oe^{-0.000867t}\\\\\\.35=e^{-0.000867t}\\\\\\ln(.35)=-0.000867t\\\\\\\dfrac{ln(.35)}{-0.000867}=t\\\\\\\large\boxed{1211.6585=t}

5 0
3 years ago
Select the solution(s) of log2x=1−log(x+4).
mart [117]

Step-by-step explanation:

log2x = 1 - log(x+4)

log2x = log10 - log(x+4)

log2x = log[10/(x+4)]

2x = 10/(x+4)

2x(x+4) = 10

2x² + 8x - 10 = 0

÷2 both sides of equation

x² + 4x - 5 = 0

(x+5)(x-1) = 0

x = -5, 1

x isn't be -5 because logA, A need to be > 0

So, x value is 1

7 0
2 years ago
Find the zeros (roots) of the following equations. f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0
Talja [164]
Hi,
f(1)=2*1^5-9*1^4+12*1^3-12*1^2+10*1-3\\&#10;=2-9+12-12+10-3\\&#10;=0\\&#10;&#10;f(x)=(x-1)(2x^4-7x^3+5x^2-7x+3)\\&#10;&#10;&#10;g(x)=2x^4-7x^3+5x^2-7x+3\\&#10;&#10;g(3)=2*3^4-7*3^3+5*3^2-7*3+3\\&#10;=162-189+45-21+3\\&#10;=0\\&#10;&#10;g(x)=(x-3)(2x^3-x^2+2x-1)\\&#10;&#10;h(x)=2x^3-x^2+2x-1\\&#10;&#10;h( \dfrac{1}{2} )=2* \dfrac{1}{8} - \dfrac{1} {4}+1-1\\&#10;=0\\&#10;&#10;h(x)=(2x-1)(x^2+1)\\&#10;&#10;&#10;f(x)=(x-1)(x-3)(2x-1)(x+i)(x-i)\\&#10;&#10;&#10;
Roots are 1,3,0.5,i,-i.

8 0
3 years ago
Write 66² as a product of its prime factors <br><br> Please ill award brainlist
mestny [16]

Answer:

11

Step-by-step explanation:

the image above explains it

8 0
1 year ago
What is the answer to this equation?
My name is Ann [436]

Answer:W ^10

Step-by-step explanation:

The solution is in the

4 0
1 year ago
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