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podryga [215]
3 years ago
9

Can someone help me with this?

Mathematics
1 answer:
timama [110]3 years ago
5 0

Answer:

-9m and 3m

and

3 and - 8

Step-by-step explanation:

In algebra, like terms are terms that have the same variables and powers. The coefficients do not need to match. Unlike terms are two or more terms that are not like terms, i.e. they do not have the same variables or powers.

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B\7+12=-8 helpppppppp
vodka [1.7K]

Answer:

b = -152

Step-by-step explanation:

  1. 7 + 12 = 19
  2. Plug 19 in: \frac{b}{19} = -8  
  3. Multiply each side by 19 to cancel out the 19 under b. It should now look like this: b = -152

I hope this helps!

8 0
2 years ago
Oml pls helppp
USPshnik [31]

Answer:

Step-by-step explanation:

y > 2/3x - 1/5

y ≥ 3/2x + 1/5

y ≤ 2/3x + 1/5

y < 3/2x - 1/5

(Assume that the question want you to draw a graph)

Remember:

> or < is a dotted line

≥ or ≤ is a solid line

8 0
2 years ago
Read 2 more answers
Angle C is an inscribed angle of circle P. Angle C measure (17x-2) and arc AB measure (20x+10). Find X
jeyben [28]
10x + 5 = 16x - 1 
<span>6x = 6 </span>
<span>x = 1 </span>
5 0
3 years ago
Could someone tell me how to do the first one and how to do the second one pleaese
Yuri [45]
1 is A
2 is coming think
7 0
3 years ago
Every day a kindergarten class chooses randomly one of the 50 state flags to hang on the wall, without regard to previous choice
Romashka [77]

Answer:

a)   S=50

    P(X)=0.02

b)  P(W,M,C)=8*10^-^6

c)  P(W_2_3)=1.18*10^-^3

Step-by-step explanation:

From the question we are told that

Sample space S=50

Sample size n=30

a)Generally the sample space S is

S=50

The probability measure is given as

P(X)=\frac{1}{50}

P(X)=0.02

b)

Generally the probability that  the class hangs Wisconsin’s flag on Monday, Michigan’s flag on Tuesday, and California’s flag on Wednesday is mathematically given as

Probability of each one being hanged is

P(X)=\frac{1}{50}

Therefore

P(W,M,C)=\frac{1}{50} *\frac{1}{50}* \frac{1}{50}

P(W,M,C)=\frac{1}{125000}

P(W,M,C)=8*10^-^6

c)Generally the probability that Wisconsin’s flag will be hung at least two of the three days is mathematically given as

Probability of two days hung +Probability of three days hung

Therefore

P(W_2_3)=^3C_2 (1/50) * (1/50) * (49/50) +^3C_3 (1/50) * (1/50) *(1/50)

P(W_2_3)=148 / 125000

P(W_2_3)=1.18*10^-^3

3 0
3 years ago
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