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2 years ago

Oml pls helppp

Mathematics

2 answers:

USPshnik [31]2 years ago

8 0

Answer:

Step-by-step explanation:

y > 2/3x - 1/5

y ≥ 3/2x + 1/5

y ≤ 2/3x + 1/5

y < 3/2x - 1/5

(Assume that the question want you to draw a graph)

Remember:

> or < is a dotted line

≥ or ≤ is a solid line

astraxan [27]2 years ago

5 0

Answer:

its c

Step-by-step explanation:

on edge 2020

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For f(x)=4sin(x2) between x=0 and x=3, find the coordinates of all intercepts, critical points, and inflection points to two dec

telo118 [61]

Answer:

Intercepts:

x = 0, y = 0

x = 1.77, y = 0

x = 2.51, y = 0

Critical points:

x = 1.25, y = 4

x = 2.17 , y = -4

x = 2.8, y = 4

Inflection points:

x = 0.81, y = 2.44

x = 1.81, y = -0.54

x = 2.52, y = 0.27

Step-by-step explanation:

We can find the intercept by setting f(x) = 0

$4sin(x^2) = 0$

$sin(x^2) = 0$

$x^2 = n\pi$ where n = 0, 1, 2,3, 4, 5,...

$x = \sqrt(n\pi)$

Since we are restricting x between 0 and 3 we can stop at n = 2

So the function f(x) intercepts at y = 0 and x:

x = 0

x = 1.77

x = 2.51

The critical points occur at the first derivative = 0

$f^{'}(x) = 4cos(x^2)2x = 8xcos(x^2) = 0$

$xcos(x^2) = 0$

$x = 0$ or

$cos(x^2) = 0$

$x^2 = \frac{\pi}{2} + n\pi$ where n = 0, 1, 2, 3

$x = \sqrt{\pi(n+1/2)}$

Since we are restricting x between 0 and 3 we can stop at n = 2

So our critical points are at

x = 1.25, $y = f(1.25) = 4sin(1.25^2) = 4$

x = 2.17 , $y = f(2.17) = 4sin(2.17^2) = -4$

x = 2.8, $y = f(2.8) = 4sin(2.8^2) = 4$

For the inflection point, we can take the 2nd derivative and set it to 0

$f^[''}(x) = 8(cos(x^2) - xsin(x^2)2x) = 8cos(x^2) - 16x^2sin(x^2) = 0$

$cos(x^2) = 2x^2sin(x^2)$

$tan(x^2) = \frac{1}{2x^2}$

We can solve this numerically to get the inflection points are at

x = 0.81, $y = f(0.81) = 4sin(0.81^2) = 2.44$

x = 1.81, $y = f(1.81) = 4sin(1.81^2) = -0.54$

x = 2.52, $y = f(2.52) = 4sin(2.52^2) = 0.27$

3 0

3 years ago

Connor went to new york for vacation. he spent 3 nights at a hotel and rented a car for 4 days. jillian stayed at the same hotel

Vikentia [17]

<em>Answer : C: $125.</em>

Hopefully that helps you ! have a good day !

8 0

3 years ago

What would this equal too look at the screen shot

jekas [21]

Given:

The figure of two parallel lines MP and QS.

A transversal line KL interests the two parallel lines.

$m\angle KNM =146^\circ$

To find:

The $m\angle KRQ$ .

Solution:

If a transversal line intersect the two parallel lines, then the corresponding angles are congruent and their measures are equal.

In the given figure $\angle KRQ$ and $\angle KNM$ corresponding angles. It means their measures are equal.

$m\angle KRQ=m\angle KNM$

$m\angle KRQ=146^\circ$

Therefore, $m\angle KRQ=146^\circ$ .

6 0

3 years ago

The ratio of girls to boys who participated in the quiz bowl was 7:5. There were 42 girls in the competition. How many boys part

Vlad1618 [11]

7*6=42 girls
5*6=30 boys
7:5=42:30
30 boys participated

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3 years ago

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Complete the inequality. 9% ___ 0.4

Alex73 [517]

9% is less than 0.4. 0.4 is really 4/10 which is 40% 40 is greater than 9 therefore 9% is less than 0.4! So your answer is 9%<0.4! I hope this helped!

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3 years ago