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sukhopar [10]
3 years ago
5

Find the missing term. The sum of______ and 7x2 is 10x2. A: -3x^2 B: 3x^2

Mathematics
2 answers:
Ilya [14]3 years ago
7 0
Your answer is b hope this helped
olga2289 [7]3 years ago
4 0
The answer is B because it can't be negative
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Find the radius pls. help
MA_775_DIABLO [31]

Good morning,

Answer:

<h2>r = 4 cm</h2>

Step-by-step explanation:

V = h × (base area)

  = 12 × (π×r²)

then 192π = 12π×r²

Then 192 = 12×r²

Then r² = 192÷12 = 16

Then r = √16 = 4.

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2 years ago
Write down the size of angle ABC give a reason your answer ​
FrozenT [24]
ABC = 180 degrees because a triangle is always equal to 180degree
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List the rst 10 terms of each of these sequences. a) the sequence obtained by starting with 10 and obtaining each term by subtra
vazorg [7]

Answer:

a) 10, 7, 4, 1, -2, -5, -8, -11, -14, -17.

c)  1, 2, 3 4 5 6 7 8 9 10.

d) √1 , √2, √3  √4 , √5, √6  √7 , √8, √9 √10.

e)     1, 5, 6, 11, 17, 28, 45, 73, 118, 191.

Step-by-step explanation:

a)  10, 10-3 , 10-3-3...

c)  3(1)- 2(1) , 3(2) - 2(2), 3(3) - 2(3),  3(4) - 2(4) ..

= 1, 2, 3, 4...

d) √1 , √2, √3 ...

e)  1, 5,  (5+6), (5 + 11)...

3 0
2 years ago
Help bc I don’t feel like solving it myself my teacher trying to keep me
galina1969 [7]

Answer: y=1x+2

Step-by-step explanation:

I think thats the answer

3 0
3 years ago
A manufacturer of nickel-hydrogen batteries randomly selects 100 nickel plates for test cells, cycles them a specified number of
kolezko [41]

Answer:

a) Parameter of interest p representing the true proportion of the plates have blistered.

b) Null hypothesis:p\leq 0.1  

Alternative hypothesis:p > 0.1  

c) z=\frac{0.14 -0.1}{\sqrt{\frac{0.1(1-0.1)}{100}}}=1.33  

d) For this case we need to find a value in the normal standard distribution that accumulates 0.1 of the area in the right tail and for this case is:

z_{critc}= 1.28

e) For this case since our calculated value is higher than the critical value 1.33>1.28 we have enough evidence to reject the null hypothesis and we can conclude that the true proportion is significantly higher than 0.1

f) p_v =P(z>1.33)=0.0917  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the true proportion is higher than 0.1 or 10%

Step-by-step explanation:

Data given and notation

n=100 represent the random sample taken

Part a

Parameter of interest p representing the true proportion of the plates have blistered.

X=14 represent the number of the plates have blistered.

\hat p=\frac{14}{100}=0.14 estimated proportion of the plates have blistered.

p_o=0.1 is the value that we want to test

\alpha=0.1 represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Part b: Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that  more than 10% of all plates blister under such circumstances.:  

Null hypothesis:p\leq 0.1  

Alternative hypothesis:p > 0.1  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Part c: Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.14 -0.1}{\sqrt{\frac{0.1(1-0.1)}{100}}}=1.33  

Part d: Rejection region

For this case we need to find a value in the normal standard distribution that accumulates 0.1 of the area in the right tail and for this case is:

z_{critc}= 1.28

Part e

For this case since our calculated value is higher than the critical value 1.33>1.28 we have enough evidence to reject the null hypothesis and we can conclude that the true proportion is significantly higher than 0.1

Part f

Since is a right taild test the p value would be:  

p_v =P(z>1.33)=0.0917  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the true proportion is higher than 0.1 or 10%

7 0
2 years ago
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