Y = (x + 2)(x − 3) Find the zero of the function

Mathematics

1 answer:

svet-max [94.6K]3 years ago

4 0

Answer:

The zeros are {-2, 3}

Step-by-step explanation:

Set each of these factors equal to zero, in turn, set each factor = to 0 and solve the resulting equation for x:

x + 2 = 0 yields x = -2;

x - 3 = 0 yields x = 3

The zeros are {-2, 3}

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Can someone help out?

Crank

Answer:

b ≥ 5,000.

Step-by-step explanation:

1. Use the information given in the problem to write the inequality... such as box tops & the amount of 5,000 box tops.

2. b represents the number of box tops for the fundraiser. Therefore, based on the information provided, the value of b must be greater than or equal to 5,000 box tops. So, you get the inequality is:

b ≥ 5,000

3. Then you graph it, you must use a closed circle for ≥.

~~(the graph is different, but you should be able to understand it.)

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6 0

3 years ago

P( rolling a number greater than 2 and the coin landing on heads or tails)

irina [24]

The value of P(rolling a number greater than 2 and the coin landing on heads or tails) is 4/6

<h3>How to determine the probability?</h3>

The given parameters are:

Objects = Dice and Coin

The sample space of the objects are:

Dice = {1, 2, 3, 4, 5, 6}

Coin = {Head, Tail}

From the above sample spaces, we have:

P(Rolling a number greater than 2) = 4/6

P(Coin landing on heads or tails) = 1

The required probability is then calculated as:

P(rolling a number greater than 2 and the coin landing on heads or tails) = P(Rolling a number greater than 2) * P(Coin landing on heads or tails)

Substitute the known values in the above equation

P(rolling a number greater than 2 and the coin landing on heads or tails) = 4/6 * 1

Evaluate the product

P(rolling a number greater than 2 and the coin landing on heads or tails) = 4/6

Hence, the value of P(rolling a number greater than 2 and the coin landing on heads or tails) is 4/6