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Hatshy [7]
3 years ago
9

The table above gives values of f, f’, g, and g’ at selected values of x. If h(x) = f(g(x)), then h’(1) =

Advanced Placement (AP)
2 answers:
Kobotan [32]3 years ago
8 0

Answer

5

Explanation

h(x) = f(g(x))

h'(x) = f'(g(x))

so h'(1) = f'(g(1))

g(1) = -1

so f'(-1) which equals 5

Therefore h'(1) = 5

Anit [1.1K]3 years ago
3 0

Answer:

h'(-1) = 5

Explanation:

Given - The table above gives values of f, f’, g, and g’ at selected values

             of x.

x              f(x)                   f'(x)                    g(x)                      g'(x)

-1              6                      5                         3                          -2

1               3                      -3                        -1                          2

3               1                      -2                         2                          3

To find - If h(x) = f(g(x)), then h’(1) = ......?

Proof -

Given that,

h(x) = f(g(x))

⇒h'(x) = f'(g(x))

⇒h'(1) = f'(g(1))

Now,

g(1) = -1

⇒f'(-1) = 5

⇒h'(-1) = 5

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