Integrate <span>f ''(x) = −2 + 36x − 12x2 with respect to x:
f '(x) = -2x + (36/2)x^2 - (12/3)x^3 + c. Find c by letting x = 0 and using f(0)=8.
Then f '(0) = -2x + 18x^2 - 4x^3 + c = 18 (which was given).
Then -0 + 0 - 0 + c = 18, so c = 18 and
f '(x) = </span>-2x + 18x^2 - 4x^3 + 18.
Go through the same integration process to find f(x).
The value of constant c for which the function k(x) is continuous is zero.
<h3>What is the limit of a function?</h3>
The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.
To determine the value of constant c for which the function of k(x) is continuous, we take the limit of the parameter as follows:
Provided that:
Using l'Hospital's rule:
Therefore:
Hence; c = 0
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Answer: The next three terms =2.56, - 1.024 and 0.4096
Step-by-step explanation:
Common Ratio of a Geometric sequence, R is calculated as
=a2/a1 = -40/100=-0.4
or a3/a2=16/ -40 = -0.4
such that the next three terms are
5th term = -6.4 x -0.4=2.56
6th term= 2.56 x -0.4 =-1.024
7TH term= -1.024 x -0.4=0.4096
we conclude that if the scale factor from S to M is 3/2, then the scale factor from M to S is 2/4.
<h3>
</h3><h3>What is the scale factor from M to S?</h3>
Suppose we have a figure S. If we apply a stretch of scale factor K to our figure S, we can say that all the dimensions of figure S are multiplied by K.
So, if S represents the length of a bar, then after the stretch we will get a bar of length M, such that:
M = S*K
If that scale factor is 3/2, then we have the case of the problem:
M = (3/2)*S
We can isolate S in the above relation:
(2/3)*M = S
Now we have an equation (similar to the first one) that says that the scale factor from M to S is 2/3.
Then we conclude that if the scale factor from S to M is 3/2, then the scale factor from M to S is 2/4.
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