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3 years ago

What is the percent of 45/100?

Mathematics

1 answer:

myrzilka [38]3 years ago

5 0

45/100 is 4,500% 2/5 is 40% 18/40 is 45% 15/25 is 60%

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oceanside bike rental shop charges a $17 fixed fee plus six dollars an hour for renting a bike. Tim paid $47 to rent a bike. How

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Approximately 8 hours

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2 years ago

Solve the inequality 3x - 5 < 4.

lbvjy [14]

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2 years ago

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Mama L [17]

Answer:

3 3/5 miles

Step-by-step explanation:

6 3/4 divided by 1 7/8=

3 3/5

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2 years ago

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From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ

bulgar [2K]

Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given by $P(x)=C(n,x)p^x(1-p)^{n-x}$ where $C(n,x)=\frac{n!}{x!(n-x)!}$
Here we're given
p=0.10 [ success = defective ]
n=3

(a) x=0
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,0)0.1^0(1-0.1)^{3-0}$
$=1(1)(0.729)$
$=0.729$

(b) x=2
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,2)0.1^2(1-0.1)^{3-2}$
$=3(0.01)(0.9)$
$=0.027$

(c) x ≥ 2
$P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}$
$=P(2)+P(3)$
$=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}$
$=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}$
$=3(0.01)(0.9)+1(0.001)1$
$=0.027+0.001$
$=0.028$

8 0

3 years ago

Kumar bought some mangoes. The price of each mango () is found to be 6 more than the total number of mangoes bought by him and t

spayn [35]

Answer:

Price = 20, Amount = 14

Step-by-step explanation:

A = Amount of Mangoes

P = Price for 1 Mango

P = A + 6

280 = P * A

insert A+6 for P

280 = (A+6) * A

280 = 6A + A²

280=1*a^2+6*a | Vertausche beide Seiten der Gleichung.

1*a^2+6*a=280 | quadratische Ergänzung: ergänze auf beiden Seiten (3)^2

1*a^2+6*a+(3)^2=3^2+280 | Rechne 3 hoch 2 aus.

1*a^2+6*a+(3)^2=9+280 | addiere 9 und 280

1*a^2+6*a+(3)^2=9+280 | Fasse die rechte Seite mit Hilfe der binomischen Formel zusammen.

1*(1*a+(3))^2=289 | Auf beiden Seiten Quadratwurzel ziehen.

1*a+(3)=+-*289^0.5

1*a_1+(3)=289^0.5

1*a_1+3=289^0.5 | Ziehe die Wurzel aus 289

1*a_1+3=17 | -3

1*a_1=14

8 0

3 years ago