Can you guys help me solve this

A hackberry tree has roots that reach a depth of

Degger [83]

Answer:

24.6967 meters

Step-by-step explanation:

The roots of the tree go 6 and 5 over 12 meters below the ground level.

Now, 6 and 5 over 12 meters is equivalent to 6.4167 meters.

Again the top of the tree is 18.28 meters high from the ground level.

Therefore, the total height of the tree from the bottom of the root to the top is

(6.4167 +18.28) = 24.6967 meters (Answer)

5 0

3 years ago

Hi need this done fast, please

Blizzard [7]

Length:
60% of 6 is 3.6

3.6 x 6 = 21.6

Width:
150% of 5 is 7.5

7.5 x 5 = 37.5

So her mothers garden should be 21.6 feet in length, and 37.5 feet in width.

5 0

3 years ago

Read 2 more answers

The endpoints of a line segment graphed on a Cartesian coordinate system are (4, 1) and (-2, -4). What are the coordinates of th

Masja [62]

The midpoint of (x1,y1) and (x2,y2) is $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

just average them

(4,1) and (-2,4)
the midpoint is $(\frac{4-2}{2},\frac{1-4}{2})=(\frac{2}{2},\frac{-3}{2})=$ (1,-1.5)

5 0

3 years ago

Read 2 more answers

How many days are there in 6 weeks? Solve the related word problem to represent the inverse operation There are days in 6 weeks

expeople1 [14]

Answer:

there a 42 days in 6 weeks

Step-by-step explanation:

multiply 6 x 7= 42

3 0

3 years ago

Evaluate the following limit:

Makovka662 [10]

If we evaluate the function at infinity, we can immediately see that:

$\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle L = \lim_{x \to \infty}{\frac{(x^2 + 1)^2 - 3x^2 + 3}{x^3 - 5}} = \frac{\infty}{\infty}} \end{gathered}$}$

Therefore, we must perform an algebraic manipulation in order to get rid of the indeterminacy.

We can solve this limit in two ways.

By comparison of infinities:

We first expand the binomial squared, so we get

$\large\displaystyle\text{$\begin{gathered}\sf \displaystyle L = \lim_{x \to \infty}{\frac{x^4 - x^2 + 4}{x^3 - 5}} = \infty \end{gathered}$}$

Note that in the numerator we get x⁴ while in the denominator we get x³ as the highest degree terms. Therefore, the degree of the numerator is greater and the limit will be \infty. Recall that when the degree of the numerator is greater, then the limit is \infty if the terms of greater degree have the same sign.

Dividing numerator and denominator by the term of highest degree:

$\large\displaystyle\text{$\begin{gathered}\sf L = \lim_{x \to \infty}\frac{x^{4}-x^{2} +4 }{x^{3}-5 } \end{gathered}$}\\$

$\ \ = \lim_{x \to \infty\frac{\frac{x^{4} }{x^{4} }-\frac{x^{2} }{x^{4}}+\frac{4}{x^{4} } }{\frac{x^{3} }{x^{4}}-\frac{5}{x^{4}} } }$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{=\lim_{x \to \infty}\frac{1-\frac{1}{x^{2} } +\frac{4}{x^{4} } }{\frac{1}{x}-\frac{5}{x^{4} } } \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\frac{1}{0}=\infty } \end{gathered}$}$

Note that, in general, 1/0 is an indeterminate form. However, we are computing a limit when x →∞, and both the numerator and denominator are positive as x grows, so we can conclude that the limit will be ∞.

5 0

2 years ago