If p(x) = 5(x²+1) + 16, what is the value of p(11)?

2 answers:

8 0

626 bc 5(11^2+1) +16

3 0

Answer: 34 but I’m not 100% sure but that might be right

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valentina_108 [34]

Step-by-step explanation:

To find the E(X) expected value, you come up with the different probabilities for each outcome
your set of outcomes after 3 tosses would be = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} where H is heads and T is tails
Each element has a probability of 1/8 so let x represent number of tails
$Probability(x)=P(x)\\P(0)=\frac{1}{8} \\P(1)=\frac{3}{8} \\P(2)=\frac{3}{8} \\P(3)=\frac{1}{8}$
The E(x)=Summation (x times P(x))
$E(X)=(0)(0.125)+(1)(0.375)+(2)(0.375)+(3)(0.125)=1.5$
Now which probability is 1.5 tails? None, so it is either 2 tails or 1 tails
So you can expect to lose money in 1 game
But as you play more games the probability of getting 3 tails becomes more and more likely, so you can expect to win in a 100 games