What is the volume of the following rectangular prism using numbers 4 1/2 and 1 1/3

4over6=24over16 explain the error in the students work

marusya05 [52]

Step-by-step explanation:

The key to solve this problem is using ratios and proportions.

The key to solve this problem is using ratios and proportions.Ratio is the relationship between two numbers, defined as the quotient of one number for the other. So: The ratio between two numbers a and b is the fraction a/b and it is read a to b. This reason can also be written a : b.

The key to solve this problem is using ratios and proportions.Ratio is the relationship between two numbers, defined as the quotient of one number for the other. So: The ratio between two numbers a and b is the fraction a/b and it is read a to b. This reason can also be written a : b.Given two reasons a/b and c/d we say that they are in proportion if a/b = c/d. The terms a and d are called extremes while b and c are the means. In every proportion the product of the extremes is equal to the product of the means: a.d = b.c

The key to solve this problem is using ratios and proportions.Ratio is the relationship between two numbers, defined as the quotient of one number for the other. So: The ratio between two numbers a and b is the fraction a/b and it is read a to b. This reason can also be written a : b.Given two reasons a/b and c/d we say that they are in proportion if a/b = c/d. The terms a and d are called extremes while b and c are the means. In every proportion the product of the extremes is equal to the product of the means: a.d = b.cA student uses the ratio of 4 oranges to 6 fluid ounces of juice to find the numbers of oranges needed to make 24 fluid ounces of juice.

The key to solve this problem is using ratios and proportions.Ratio is the relationship between two numbers, defined as the quotient of one number for the other. So: The ratio between two numbers a and b is the fraction a/b and it is read a to b. This reason can also be written a : b.Given two reasons a/b and c/d we say that they are in proportion if a/b = c/d. The terms a and d are called extremes while b and c are the means. In every proportion the product of the extremes is equal to the product of the means: a.d = b.cA student uses the ratio of 4 oranges to 6 fluid ounces of juice to find the numbers of oranges needed to make 24 fluid ounces of juice.

The key to solve this problem is using ratios and proportions.Ratio is the relationship between two numbers, defined as the quotient of one number for the other. So: The ratio between two numbers a and b is the fraction a/b and it is read a to b. This reason can also be written a : b.Given two reasons a/b and c/d we say that they are in proportion if a/b = c/d. The terms a and d are called extremes while b and c are the means. In every proportion the product of the extremes is equal to the product of the means: a.d = b.cA student uses the ratio of 4 oranges to 6 fluid ounces of juice to find the numbers of oranges needed to make 24 fluid ounces of juice. The error in the student's work was that they reversed the reason, 24/16 instead of 16/24.

6 0

3 years ago

Find the value of X.

nataly862011 [7]

RS + ST = RT

3x + 1 + 2x - 2 = 64
5x - 1 = 64
5x = 64 + 1
5x = 65
x = 65/5
x = 13 <==

7 0

4 years ago

Find the area of the figure in the image attached. Round to the nearest tenth if necessary.

ella [17]

19.8m²

Work:
First you split the shape into a rectangle and a triangle. So now you have a triangle with the sides 4 x 3.6 and a triangle with the sides 4 x 2.7.

Side note: 2.7 comes from subtracting 3.6 off of 6.3.

Rectangle:
A = lw
A = 4 (3.6)
A = 14.4m²

Triangle:
A = 1/2lw
A = 1/2 (4) (2.7)
A = 5.4m²

Then you add the areas of both the rectangle and the triangle together.

14.4 + 5.4 = 19.8m²

5 0

3 years ago

Read 2 more answers

48

Diano4ka-milaya [45]

2.20 kg + 1.90 kg

*1*
2.20
+1.90
4.10

Ans=4.10 kg

4 0

3 years ago

Find the inverse laplace transform of: (2 s + 4) / (s - 3)^3

Serhud [2]

Answer:

$e^{3t}(2t+5t^{2})$

Step-by-step explanation:

$L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=$

Using the Translation theorem to transform the s-3 to s, that means multiplying by and change s to s+3

Translation theorem: $L^{1} [F(s-a)=L^{-1}[F(s)|_{s \to s-a}\\ L^{1} [F(s-a)=e^{at} f(t)$

$L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=e^{3t} L^{-1}[\frac{2(s+3)+4}{s^{3}} ]$

Separate the fraction in a sum:

$e^{3t} L^{-1}[\frac{2s+10}{s^{3}} ]=e^{3t} L^{-1}[\frac{2s}{s^{3}}+\frac{10}{s^{3}} ]=e^{3t} (L^{-1}[\frac{2}{s^{2}}]+ L^{-1}[\frac{10}{s^{3}}])$

The formula for this is:

$L^{-1}[\frac{n!}{s^{n+1}} ]=t^{n}$

Modify the expression to match the formula.

$e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ \frac{10}{2} L^{-1}[\frac{2}{s^{2+1}}])=e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])$

Solve

$e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])=e^{3t}(2t+5t^{2} )$

6 0

3 years ago