Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
Answer:
its 55
Step-by-step explanation:
Step-by-step explanation:
please mark me as brainlest
2 3/4 * 3.36 / (1 2/5)
=11/4 * 3.36 / (7/5)
= 9.24 / (7/5)
= 9.24 / 1.4
= 6.6
Answer:
Produce only Product B.
Step-by-step explanation:
The contribution margin per machine hour for product A is ...
($16 -$6)/(5 hour) = $2 per hour
The contribution margin per machine hour for product B is ...
($12 -$5)/(3 hour) ≈ $2.33 per hour
The company should produce the maximum possible number of the product that contributes the most per machine hour: Product B.
