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3 years ago

Which of the following set of ordered pairs represents a function?

Mathematics

1 answer:

Marina86 [1]3 years ago

7 0

Answer:

the answer is c because your x values are not repeating

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Which expression is equivalent to \frac{10q^5w^7}{2w^3}.\ \frac{4\left(q6\right)^2}{w^{-5}} for all values of q and w where the

mestny [16]

Answer:

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9$

Step-by-step explanation:

Given

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Required

Determine the equivalent expression

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Simplify the first fraction

$\frac{5q^5w^7}{w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Apply law of indices on the first fraction;

$5q^5w^{7-3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

$5q^5w^4.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

$\ \frac{5q^5w^4*4\left(q^6\right)^2}{w^{-5}}$

Apply law of indices:

$5q^5w^4*4\left(q^6\right)^2 * w^{5}$

Evaluate the bracket

$5q^5w^4*4 * q^{12} * w^{5}$

Collect Like Terms

$5*4q^5* q^{12}*w^4 * w^{5}$

$20q^5* q^{12}*w^4 * w^{5}$

$20q^{5+12}*w^{4+5}$

$20q^{17}w^9$

Hence:

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9$

7 0

3 years ago

On February 1, the electricity meter reading for the Smith residence was 19,423 kilowatt hours. On March 1, the meter read 20,28

Karolina [17]

A. How many kilowatt hours of electricity did the Smiths use during February?

Kilowatt hours of electricity the Smiths used during February:
Meter read on March 1 - meter read on February 1 =
20,288 kilowatt hours - 19,423 kilowatt hours =
865 kilowatt hours
Answer: The Smiths used 865 kilowatt hours of electricity during February

b. How many kilowatt hours did they use during March?

Kilowatt hours of electricity the Smiths used during March:
Meter read on April 1 - meter read on March 1 =
21,163 kilowatt hours - 20,288 kilowatt hours =
875 kilowatt hours
Answer: The Smiths used 875 kilowatt hours of electricity during March

8 0

4 years ago

Mathematics question

djyliett [7]

Answer:

Step-by-step explanation:

KL=1/2 YX=1/2×56=28

YZ=2JK=2×38=76

LZ=1/2YZ=1/2×76=38

3 0

3 years ago

Read 2 more answers

At the malt shop a large chocolate shake takes 8/9 of a pint of milk.If the medium shake takes 1/7 the amount of the large how m

omeli [17]

There are several information's of immense importance in the problem. Based on these information's the answer to the question can be easily reached. The only thing that has to be kept in mind is the calculation part, otherwise it is a simple problem.
Now it is given that:
A large chocolate shake takes 8/9 of a pint of milk.
Then
Amount of milk required to make medium shake = (8/9) * (1/7) of a pint
= 8/63 of a pint
Then it can be said that for making a medium chocolate shake , 8/63 of a pint of milk is required. This is the simplest form of the fraction and it cannot be expressed as a mixed number since the denominator is higher than the numerator.

8 0

4 years ago

PLEASE HELP I WILL MARK YOU BRAINIEST

quester [9]

Answer:

The answer is (D) y < 4

4 0

3 years ago

Read 2 more answers

Which of the following set of ordered pairs represents a function?￼

Which of the following set of ordered pairs represents a function?