Let X(t)=the position function with respect to time, t.
We're given:
X(0)=12 (from graph)
v(0)=0
X(2.5)=7
There is enough information to construct X(t).
In general,
X(t)=kt^2+v(0)(t)+x0
where initial velocity=v(0)=velocity at time 0 = 0 (given)
x0=initial position at time 0 = 12 (from graph)
Substituting values, the position equation is
X(t)=kt^2+12
Substituting given value X(2.5)=7 => 7=k(2.5^2) + 12
Solve for k to get k=(12-7)/6.25 = -4/5
The position equation now becomes
X(t)=-4t^2/5+12
For t=25,
X(25)=-4(25^2)/5+12=-500+12 = 488 m
I can’t see your choices, but this equation can be simplified to 5y + 5.
If you add the choices as a comment, I’m happy to help more.
Answer:
90
Step-by-step explanation:
1st you solve for the 8-2 in the parentheses
[3 x 6] 5
Then solve what's in the brackets
[18]5
18 x 5 = 90
1.7 I think the y values are suppose to be in order or its probably a no solution equation
Answer:
48
Step-by-step explanation:
it will travel 48 m in 3 sec