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3 years ago

The points (–4, –3) and (–1, –8) are on a line. Find the intercepts to the nearest tenth.

1 answer:

4 0

The intercepts are the points where the line meets with the x axis and the y axis. First let us find the equation of the line.

Finding slope:

slope=change in y/change in x (y2-y1/x2-x1)

slope=-3-(-8)/-4-(-1)=5/-3=-5/3

Finding y-intercept:

y=mx+b

-8=-5/3(-1)+b

b=-9 2/3

y intercept: (0,-9 2/3)

Equation: y=-5/3x-9 2/3

Since we already have the y intercept let us find the x intercept by plugging 0 in the place of y in the equation.

0=-5/3x-9 2/3

x=29/3x(-3/5)

x=-29/5

x intercept: (-29/5,0)

answers: (0,-9 2/3) and (-29/5,0)

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The ____________________ school, led by naturalist john muir, wanted wilderness areas on some public lands to be left untouched.

Vanyuwa [196]

The preservation/list school, led by naturalist John muir, wanted wilderness areas on some public lands to be left untouched.

<h3>What does it mean if a person is a naturalist?</h3>

A naturalist lifestyle is a term that connote that a person is making or developing values that makes or forms empathy and caring in regards to nature.

Therefore, The preservation/list school, led by naturalist John muir, wanted wilderness areas on some public lands to be left untouched.

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2 years ago

Graph the equation. y=2/3×-8

nordsb [41]

Answer:

place your dot at (0,-8) go up 2 and over right 3

Step-by-step explanation:

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3 years ago

Helppppp! Which answer choice correctly describes the relationship between two of the lines in the figure?

Delicious77 [7]

I would have to say that it is the 3rd answer choice due to the right angle that is formed between line C and line A.

8 0

3 years ago

Read 2 more answers

Three trigonometric functions for a given angle are shown below. cosecant theta = thirteen-twelfths; secant theta = Negative thi

Kay [80]

Answer:

(–5, 12) is the correct answer.

Step-by-step explanation:

We are given the following values:

$cosec\theta = \dfrac{13}{12}\\sec\theta=-\dfrac{13}{5}\\cot\theta =-\dfrac{5}{12}$

Now, we know the following identities:

$sin \theta = \dfrac{1}{cosec\theta}\\cos \theta = \dfrac{1}{sec\theta}\\tan \theta = \dfrac{1}{cot\theta}$

Now, the values are:

$sin\theta = \dfrac{12}{13}\\cos\theta=-\dfrac{5}{13}\\tan\theta =-\dfrac{12}{5}$

Sine value is positive and cos, tan values are negative.

It can be clearly observed that $\theta$ is in 2nd quadrant.

2nd quadrant means, the value of $x$ will be negative and $y$ will be positive.

Let us have a look at the value of $tan\theta$ :

$tan\theta = \dfrac{Perpendicular}{Base}\\OR\\tan\theta = \dfrac{y-coordinate}{x-coordinate} = -\dfrac{12}{5}\\\therefore y = 12,\\x = -5$

Please refer to the attached image for clear understanding and detailed explanation.

Hence, the correct answer is coordinate (x,y) is (–5, 12)

8 0

3 years ago

(6v^3+42v)/(2v^2+26v+84)

Kisachek [45]

Answer:
_______________________________________________
The simplied version is:
_______________________________________________
" $\frac{3v(v^2+7)}{(v^2+13v+42)}$ " ;

or; write as: " $\frac{3v(v^2+7)}{(v+7)(v+6)}$ " .
_______________________________________________
Explanation:
_______________________________________________
Given:
_______________________________________________
" $\frac{6v^3 +42 v}{2v^2 +26v + 84}$ " ;
_______________________________________________
→ Factor out a "6v" $\frac{6v(v^2+7)}{2(v^2+13v+42)}$ in the "numerator"; & factor out a "2" in the denominator; as follows:
____________________________________
→ $\frac{6v(v^2+7)}{2(v^2+13v+42)}$ ;
____________________________________
→ " $\frac{3v(v^2+7)}{(v^2+13v+42)}$ " ;
______________________________________________

or; factor out the "denominator" :
______________________________________________
→ (v² + 13v + 42) = (v+7)(v+6) ;
______________________________________________
and write as:
______________________________________________
→ " $\frac{3v(v^2+7)}{(v+7)(v+6)}$ " .
______________________________________________

3 0

4 years ago