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3 years ago

Solve the following system of inequalities graphically on the set of axes below. State

Mathematics

1 answer:

Aneli [31]3 years ago

5 0

Answer:

x-intercept (and intersection of both lines)- (-3,0)

Step-by-step explanation:

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What is 0.79 as a percent

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79 percent is the answer

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3 years ago

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What is the equation of the line that passes through the point(-8,1) and has a slope of -3/4

vodka [1.7K]

Answer:

slope = -3/4

using the formula

y -y1 = m(x -x1)

y -1 = -3/4(x -(-8))

y -1 = -3/4(x +8)

cross multiply

4(y -1) = -3(x +8)

4y -4 = -3x -24

4y = -3x -24 +4

4y = -3x -20

divide both sides by 4

y = -3/4 x -5 (equation of the line)

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3 years ago

A blueprint of a plot of land has a scale of 1 1/2 cm to m. The length of land measures 15 cm on the blueprint. If l represents

spayn [35]

Answer: l = 82.5m

Step-by-step explanation:

11/2 x 15 = 82.5

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4 years ago

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Stuart paid $ 48.00 for a New tennis racket ,which was 64% of the original price what was the original price of the racket.

Trava [24]

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4 years ago

Suppose we want to choose 5 colors, without replacement, from 8 distinct colors.1. If the order is relevant, how many can be don

Charra [1.4K]

(1) From the information given, if we want to choose 5 colors from 8 distinct colors and the order in which the selection is made is relevant, then what we have is a permutation.

The formula is given as;

$nP_r=\frac{n!}{(n-r)!}$

This formula means we need to select/arrange r items out of a total of n items and the anwer derived would be the total number of arrangements possible.

Therefore, we would have;

$\begin{gathered} nP_r\Rightarrow_8P_5 \\ _8P_5=\frac{8!}{(8-5)!}\Rightarrow\frac{8!}{3!} \\ _8P_5=\frac{8\times7\times6\times\ldots1}{3\times2\times1}\Rightarrow\frac{40320}{6} \\ _8P_5=6720 \end{gathered}$

Therefore, if the order is relevant, this selection can be done in 6,720 ways.

(2) If the order is NOT relevant, then what we need to calculate is a combination and the formula is;

$_nC_r=\frac{n!}{(n-r)!r!}$

The formula can now be applied as follows;

$\begin{gathered} _nC_r\Rightarrow_8C_5 \\ _8C_5=\frac{8!}{(8-5)!\times5!} \\ _8C_5=\frac{8!}{3!\times5!}\Rightarrow\frac{8\times7\times6\times\ldots1}{(3\times2\times1)\times(5\times4\times\ldots1)} \\ _8C_5=\frac{40320}{6\times120} \\ _8C_5=56 \end{gathered}$

If the order is not relevant, then the selection can be done in 56 ways.

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1 year ago