I would have to see the shape to see this but I could say the volume if you'd want. 5*6*7= 210. And don't forget; you can find the surface area by doing b x h if it's a rectangle. And if it's a triangle do b x h / 2
Since length*width=area, (x+12)*width=x²-144. Dividing (x+12) from both sides, we get (x²-144)/(x+12)=width. One formula we can use is that
(a²-b²)=(a-b)*(a+b). Since 144=12², that means that x²-144=(x-12)*(x+12). Plugging that in, we get (x-12)*(x+12)/(x+12)=(x-12)=width
The first option is the answer you are looking for.
Answer:
The required thickness of the tank wall is 87.7668 mm.
Step-by-step explanation:
Given :
Volume of vessel is V=1.5 m³.
A spherical pressure vessel is of compressed natural gas at P=22 MPa.
If the tank is made of A516 grade 60 steel with a maximum normal stress 150 MPa.
i.e. 
To find : What is the required thickness of the tank wall?
Solution :
The diameter of the vessel is given by,
Convert into mm,
The thickness of the wall tank is given by,
Therefore, the required thickness of the tank wall is 87.7668 mm.
Answer:
First side is 19, second side is 38 and third side, the longest is 43.
Step-by-step explanation:
Let's call the first side a.
The second side, being twice as long as the first, is 2a.
The third side is 2a+5.
The equation is:
a+2a+2a+5=100, since 1 metre is 100 centimetre.
5a+5=100
5a=95
a=19
First side is 19, second side is 38 and third side, the longest is 43.
