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kondor19780726 [428]
2 years ago
6

Simplify :(

Mathematics
1 answer:
evablogger [386]2 years ago
4 0
<h3>Answer:</h3>

8

<h2><u>STEPS:</u></h2>

=57 times 4/57 times 2

=57/1 times 4/57 times 2

=4/2 times 2 (cancel common factor:57)

=4/1 times 2 (convert element to fraction 2= 2/1)

=4/1 times 2/1

Multiply the numbers (4 times 2)

=8/1 times 1 (Multiply the numbers 1 times 1)

Apply the fraction rule: a/1 =9

=8

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Find a polynomial with a degree of 3 and zeros -3,3,5
Aliun [14]

Answer:

f(x) = x³ - 5x² - 9x + 45

Step-by-step explanation:

Given x = a, x = b are the zeros of a polynomial, then

(x - a), (x - b) are the factors and f(x) is the product of the factors.

Here the zeros are x = - 3, x = 3 and x = 5, thus

(x + 3), (x - 3) and (x - 5) are the factors and

f(x) = (x + 3)(x - 3)(x - 5) ← expand the first pair of factors using FOIL

     = (x² - 9)(x - 5) ← distribute

    = x³ - 5x² - 9x + 45

   

6 0
3 years ago
La figura mostrada se dividió en tres partes iguales para calcular su área.
levacccp [35]

Answer:

El área de un rectángulo de largo L y ancho A es: L*A.

El área de un triangulo de alto H y base B es: H*B/2.

Ahora veamos las tres figuras:

Rectángulo amarillo:

Largo = 40m

Ancho = 45m

Área = 40m*45m = 1800 m^2

Rectángulo blanco:

Largo = 40m

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Área = 40m*35m = 1400m^2

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8 0
3 years ago
How do you do this question?
raketka [301]

Answer:

The required relation is,

  \frac {dV}{dt} = c{\frac{dT}{dt}}

Step-by-step explanation:

We know that for a certain amount of dry gas when the pressure is kept constant it's volume V and temperature T is related by the function,

V = cT -----------------------(1) [where "c" is a constant]

So, in that case rate of change of volume(V) with respect to time (t),

             = \frac {dV}{dt}

will be equal to ,

               c{\frac{dT}{dt}}

where \frac {dT}{dt}  is equal to rate of change of temperature (T) with  respect to time (t) and c is the constant stated before.

So, the required relation is,

  \frac {dV}{dt} = c{\frac{dT}{dt}}

6 0
2 years ago
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