The subtraction of complex numbers 
is cos(π)+i sin(π).
Given 
[cos(3π/4+i sin(3π/4) and 
=cos (π/2) +i sin(π/2)
We have to find the value of .
A complex number is a number that includes real number as well as a imaginary unit in which 
. It looks like a+ bi.
We have to first solve 
and then we will be able to find the difference.
[ cos (3π/4)+i sin (3π/4)]
[cos(π-π/4)+ i sin (π-π/4)]
= [-cos(π/4)+sin (π/4)]
=(-1/+1/)
=
=0
cos(π/2)+i sin (π/2)
=0+i*1
=1
Now putting the values of 
,
=-1
=-1+i*0
=cos (π)+i sin(π)
Hence the value of difference between is cos(π)+i sin(π).
Learn more about complex numbers at brainly.com/question/10662770
#SPJ4
Answer:
1/6
Step-by-step explanation:
Divide by 3
9/54 = 3 / 18
You can again divide by 3 for the answer
1/6
Answer:
9^-3/9^12
Step-by-step explanation:
Answer:
Not sure what you're asking but 120.4 is
one hundred
two tens
and four tenths
Convention in algebra is that we use letters such as a, b, c, etc., for parameters and letters such as x, y z, and so on, for variables.
Thus the parameters here are a, b and k. k is the constant of proportionality.
