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3 years ago

Write three numbers that have GCF of 7

Mathematics

2 answers:

Galina-37 [17]3 years ago

7 0

Answer:

21, 35 , 49

Step-by-step explanation:

21 = 3 * 7

35 = 5 * 7

49 = 7 * 7

GCF = 7

xeze [42]3 years ago

6 0

21,35,49 more s the answer of the 3 GCF of 7

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What is the answer to this question

posledela

<em>The best answer from the choices provided is option </em><u>B) 56.</u>

Step-by-step explanation: Simply subtract 34 from 90.

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3 years ago

How far does the tip of the minute hand of a clock move in 1 hour and 27 minutes if the hand is 2 inches long?

Nesterboy [21]

So, a full circle has 360°, thus when the minute hand does one hour, it does a full circle, therefore 360°.

now, how many degrees are there in 1 minute? well, there are 60 minutes in 360°, therefore there are 360/60 degrees in 1 minute, or 6°.

now, we know in 1 hour there are 360°, how many in 27 minutes? well, 27 * 6, or 162°. So after 1hr and 27min, the minute hand has done 360+162 or 522°.

we also know the minute hand is 2 inches long, thus

$\bf \textit{arc's length}\\\\
s=\cfrac{\pi \theta r}{180}\quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
r=2\\
\theta =522
\end{cases}\implies s=\cfrac{\pi \cdot 522\cdot 2}{180}$

which is roughly 18 inches rounded up.

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3 years ago

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timurjin [86]

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3 years ago

Topic: The Quadratic Formula

Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

$x= \frac{-b +- \sqrt{b^2-4ac} }{2a}$

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² = x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

$x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\= -4 or 1$

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

$x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\$

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

$x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2$

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

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3 years ago

What are the prime numbers

AysviL [449]

Prime numbers are only divisible by 1 or itself; the first few are are 2, 3, 5, 7, and 11.

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3 years ago

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Write three numbers that have GCF of 7​

Write three numbers that have GCF of 7