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BartSMP [9]
3 years ago
8

Please help with my questions...

Mathematics
1 answer:
FrozenT [24]3 years ago
7 0

Answer:

20 X 1/20 = 1

10 X 1/10 = 1

Step-by-step explanation:

I hope that helps.

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Rise is 35, run is 1
35 is the answer

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3 years ago
What is 3 4/8 + 7 1/2
vivado [14]

Answer:

11

Step-by-step explanation:

3+7=10

4/8=1/2

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Solve for x. <br> 2(x-2)= 6x + 2 -2(-2x - 4)
Lena [83]

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Step-by-step explanation:

2(x-2)=6x+2-2(-2x-4)

Open brackets

2x-4=6x+2+4x+8

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4 years ago
How wide is the hole at ground level on the drawing
Bumek [7]

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4 years ago
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(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t&lt;00≤t&lt;11≤t&lt;7t≥7;f(t)={0,t&lt;0−5,0≤t&lt;1−6,1≤t&lt;76,t≥7; 1. wr
sergij07 [2.7K]
f(t)=\begin{cases}0&\text{for }t

Recall that

u(t)=\begin{cases}0&\text{for }t

Take it one piece at a time. For t\ge0, we can scale u(t) by -5:

-5u(t)=\begin{cases}0&\text{for }t

If we shift the argument by 1 and scale by -5, we have

-5u(t-1)=\begin{cases}0&\text{for }t

so if we subtract this from -5u(t), we'll end up with

-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t

For the next piece, we can add another scaled and shifted step like

-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t

so that

-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t

For the last piece, we add one more term:

6u(t-7)=\begin{cases}0&\text{for }t

and so putting everything together, we get f(t):

f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)
f(t)\equiv-5u(t)-u(t-1)+12u(t-7)
5 0
3 years ago
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