Question

A jar contains 38 red marbles numbered 1 to 38 and 38 blue marbles numbered 1 to 38 a marble is drawn at random from the jar

Answer 1

Answer:

$P(Red) = 0.50$'

$P(Odd) = 0.50$

Step-by-step explanation:

Given

$Red = 38$

$Blue = 38$

Required (Missing part of the question)

(a) The marble is red. (b) The marble is odd-numbered

Solving (a): Probability of Red.

This is calculated as:

$P(Red) = \frac{Red}{Total}$

$P(Red) = \frac{38}{38+38}$

$P(Red) = \frac{38}{76}$

$P(Red) = 0.50$

Solving (b): Probability of Odd

Since each marble type is numbered 1 to 38, then half of it are odd.

i.e. 19 odd numbered red marbles and 19 odd numbered blue marbles.

So, the probability of odd is:

$P(Odd) = \frac{Odd}{Total}$

$P(Odd) = \frac{19+19}{38+38}$

$P(Odd) = \frac{38}{76}$

$P(Odd) = 0.50$