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kifflom [539]
3 years ago
8

Graph the line with intercept 6 and slope

la1" title=" - \frac{3}{2} " alt=" - \frac{3}{2} " align="absmiddle" class="latex-formula">
​

Mathematics
1 answer:
Ksivusya [100]3 years ago
4 0

Given:

The y-intercept of a line = 6

The slope of the line = -\dfrac{3}{2}

To find:

The graph of the given line.

Solution:

The slope intercept form of a line is:

y=mx+b

Where, m is the slope and b is the y-intercept.

Putting m=-\dfrac{3}{2} and b=6 in the above equation, we get

y=-\dfrac{3}{2}x+6

At x=0,

y=-\dfrac{3}{2}(0)+6

y=0+6

y=6

At x=2,

y=-\dfrac{3}{2}(2)+6

y=-3+6

y=3

Plot these two points (0,6) and (2,3) on a coordinate plane and connect them by a straight line to get the graph of the required line.

The required graph is shown below.

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Step-by-step explanation:

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How much would it cost to buy a piece of candy for 50 cents plus tax
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2 years ago
This circle is centered at the origin, and the length of its radius iS 6. What is
VikaD [51]

\sf{\qquad\qquad\huge\underline{{\sf Answer}}}

The equation of circle in standard form can be represented as :

\qquad \sf  \dashrightarrow \:(x - h) {}^{2}  + (y - k) {}^{2}  = r {}^{2}

where,

  • h = x - coordinate of centre = 0

  • k = y - coordinate of centre = 0

  • r = radius of circle = 6 units

now, let's plug in the values :

\qquad \sf  \dashrightarrow \:(x - 0) {}^{2}  + (y - 0) {}^{2}  = 6 {}^{2}

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