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prohojiy [21]
3 years ago
5

KIS+KSI=ISK WHAT IS THE NUMBERS?!?!??!?

Mathematics
2 answers:
White raven [17]3 years ago
7 0
KIS = 11,199
KSI= 11919
ISK= 91911

Means- 11,199+11,919= 91911
Hope this helps!
8090 [49]3 years ago
5 0
Is this a real question ?
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Help meeeeeeeeeeeeeeeeeeeeeeeeeeee
pochemuha

Answer:

3

Step-by-step explanation:

I think the easiest way to go about this is to choose on of the answers and fill it in to see if it's correct. Since you only have 4 possible answers, there's no need to actually solve this.

In the question it already tells us that x does not equal 0, so that answer is automatically not correct. Now your down to three possible answers.

Start with -3. First, fill in the x with -3 for what the equation is supposed to equal. That gives you 3/-3. Simplified, that is -1. Now put -3 in for the x in the equation. That gives you 3/2(-3) + 1/2. After running that through your calculator or solving it, you end up with 0. So -3 is not your answer.

Next we'll try the 2. Do as we did last time, and fill in the x on the answer part of the equation. You now have 3/2. That doesn't simplify so it stays as is. Now for the equation. That makes it 3/2(2) +1/2. Put that in your calculator or solve, and you get 5/4. 5/4 does not equal 3/2 so 2 is not your answer.

That leaves 3. You can go ahead and run through the steps above using 3 if you want to double check, but since it's the only answer left, there isn't really a need to.

Hope this helps :)

6 0
3 years ago
Find the arrival time if the plane took off at 8:35 A.M. and flew for 2 hr. 55 min. Include A.M. or P.M. in your answer.
FrozenT [24]
11:30 am. 8:35 + 2 hours = 10:35 + 5 mins = 10:40 + 50 mins = 11:30 am
3 0
3 years ago
The growth of a strain of bacteria can be modeled by the function graphed, where the x-values are the time in seconds and the y-
Andrew [12]

There are (A) 2.7 bacterias initially.

<h3>What is a function?</h3>
  • A function is an expression that establishes the relationship between the dependent and independent variables.
  • A function from a set X to a set Y allocates exactly one element of Y to each element of X.
  • The set X is known as the function's domain, while the set Y is known as the function's codomain.
  • Originally, functions were the idealization of how a variable quantity depends on another quantity.

To find the number of bacteria:

  • The graph shows that the function follows an exponential curve, and the starting point is at ( 0,2.7 ).
  • The starting number of bacteria is then 2.7.

Therefore, there are (A) 2.7 bacterias initially.

Know more about functions here:

brainly.com/question/25638609

#SPJ4

The correct question is given below:
The growth of a strain of bacteria can be modeled by

the function graphed, where the x-values are the time

in seconds and the y-values are the number of

bacteria. How many bacteria are there initially?

(A) 2.7

(B) 2.8

(C) 4

3 0
2 years ago
You want to buy a bouquet of yellow roses and baby’s breath for $16 the baby’s breath cost $3.50 per bunch, and the roses cost $
Stolb23 [73]

•.,¸¸,.•´¯     '     ¯´•.,¸¸,.•`

: 5 !!! !

3 0
3 years ago
adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the
Zigmanuir [339]

Answer:

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659 and \left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

Step-by-step explanation:

The equation of the isotope decay is:

\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

\tau = \frac{5568\,years}{\ln 2}

\tau \approx 8032.926\,years

The decay time is:

t = 1315\,years + 2007\,years \pm 13\,years (There is no a year 0 in chronology).

t = 3335 \pm 13\,years

Lastly, the relative amount is estimated by direct substitution:

\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659

\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

4 0
3 years ago
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