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3 years ago

Can someone help me pls

Mathematics

1 answer:

olasank [31]3 years ago

3 0

BOC= 42 the value of x is 11 and you plug that in for the equations knowing that the figure comes to a right angle

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PLZ help its due at 11:59

blagie [28]

Step-by-step explanation:

Given:

Complementary angle = 68'

Angle measure = 90' - 68' = 22'

Supplementary angle = 180' - 22' = 158'

Angle classification = Acute angle

Given:

Supplementary angle = 161'

Angle measure = 180' - 161' = 19'

Complementary angle = 90' - 19' = 71'

Angle classification = Acute angle

Given:

Angle measure = 136'

Angle classification = Obtuse angle

Complementary angle = 136' - 90' = 46'

Supplementary angle = 180' - 136' = 44'

3 0

4 years ago

Solve the formula A =1/2 b*h for h

12345 [234]

$A=\dfrac{1}{2}bh\ \ \ \ |multiply\ both\ sides\ by\ 2\\\\2A=bh\ \ \ \ |divide\ both\ sides\ by\ b\\\\\boxed{h=\frac{2A}{b}}$

6 0

4 years ago

A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y

siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32

Given that 100 beetles are released into a field.

So that means initial number of beetles P=100

Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

$A=P(1+r)^n$ where A is number of beetles at any year n.

Plug the given values into above formula we get:

$A=100(1+0.32)^n$

$A=100(1.32)^n$

now plug n=10 years

$A=100(1.32)^{10}=100(16.0597696605)=1605.97696605$

Hence answer is approx 1606 beetles will be there after 20 years.

Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

$A=100(1.32)^{20}=100(257.916201549)=25791.6201549$

Hence answer is approx 25791 beetles will be there after 20 years.

Now we have to find time for 100000 beetles so plug A=100000

$A=100(1.32)^n$

$100000=100(1.32)^n$

$1000=(1.32)^n$

$log(1000)=n*log(1.32)$

$\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n$

33.174666862=n

Hence answer is approx 33 years.

4 0

4 years ago

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Write the number in two other forms 8.517

8090 [49]

8,517 8,000+500+10+7

7 0

3 years ago

Subtract 491.67−25.86 HELP!!

BabaBlast [244]

Answer:

465.81

Step-by-step explanation:

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3 years ago

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