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olga nikolaevna [1]
3 years ago
7

What is 10% of 100? Explain your work

Mathematics
2 answers:
Papessa [141]3 years ago
6 0

Answer:

10

Step-by-step explanation:

first turn percent into decimal,

10/100 = 0.10

then multiply 100 x 0.10 = 10

so therefore 10% 0f 100 is 10

Dominik [7]3 years ago
4 0

Answer: 10

Step-by-step explanation:

So, basically its just like 10 x 10. If you have 100 10% of 100 is 10

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Elise and her dad are planning to attend the state fair. An adult ticket is $21.00. The price of an adult ticket is $10.00 more
sashaice [31]

Answer:The equation to determine how much Elise will pay for a student ticket is 2x = 33

Step-by-step explanation:

Let x represent the price of one student ticket.

Elise and her dad are planning to attend the state fair and the price of an adult ticket is $21.00

The price of an adult ticket is $10.00 more than two thirds the price of a student ticket. This means that

21 = 2/3 × x + 10

The equation to determine how much Elise will pay for a student ticket would be

2x/3 + 10 = 21

2x/3 = 21 - 10 = 11

2x = 11×3 = 33

x = 33/2 = $16.5

5 0
3 years ago
(3+5)x7-[10+(45-15)\5]
Gelneren [198K]
Use\ PEMDAS\\\\(3+5)\times7-[10+\frac{(45-15)}{5}]=(8)\times7-(10+\frac{30}{5})\\\\=56-(10+6)=56-16=\boxed{\boxed{40}}
7 0
3 years ago
The revenue for a company producing widgets is given by y = -20x2 - 50x + 200, where x is the price in dollars for each widget.
lisov135 [29]

Answer:

The  price is   x =  $2.779

Step-by-step explanation:

From the question we are told that

  The  revenue is  y = - 20x^2  - 50 x + 200

   The cost of production is  y = 30 x - 10

Generally at break even point the cost of production is equal to the  revenue

So

      -20x^2 -50x + 200 =  30x-10

=>   20x^2 +20 -210 = 0

Using the quadratic formula to solve this equation we have that

       x =  $2.779

     

6 0
3 years ago
Read 2 more answers
Which pair of equations can be used to solve for x in PQR?
almond37 [142]

Answer:

A

Step-by-step explanation:

sin57° = \frac{opposite}{hypotenuse} = \frac{PQ}{PR} = \frac{x}{18}

∠ P = 180° - (90 + 57)° ← sum of angles in triangle

∠ P = 180° - 147° = 33° , then

cos33° = \frac{adjacent}{hypotenuse} = \frac{PQ}{PR} = \frac{x}{18}

Thus the 2 ratios used to solve for x are A

7 0
3 years ago
Lines g,h and l are parallel and m&lt; 2 = 129<br> What is the m &lt; L
Bingel [31]
180-129= 51
angle 4 is equal to angle 12 so missing angle 12= 51°
6 0
3 years ago
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