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pishuonlain [190]
2 years ago
9

What is the slope of the line that passes through (-1.5, -3)

Mathematics
1 answer:
Hoochie [10]2 years ago
4 0

Answer:

1/2 if it is linear

Step-by-step explanation:

Hope this helps!

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Pls anwers the question pls it has pictures as well pls pls pls pls pls pls pls
azamat

Answer:

a = $80.3

b = $80

c = 4

d = 16

e = 4

f = 88

g = $132

h = 33%

i = 6

j = 30

k = 21

l = $90

m = $36

o = 21/50

p = 105

q = 7

r = 8 cm

s = 2.4

t = 4

u = 400cm

v = $280

Step-by-step Explanation:

==>Increasing $72 by 10% to get a

a = 110% of $72 = 110% × $73

a = 1.1 × 73

a = $80.3

==>a ($80.3) rounded to the nearest 10 to find b = $80

b = $80

==>Writing b (80) as the product of its primes I.e.

b = 2^{c} * 5

Thus, 80 = 2⁴ * 5

c = 4

==>Calculating c² = d

d = 4² = 16

d = 16

==> ²/8 of d = e

e = ²/8 × 16

e = 2 × 2

e = 4

==> e% of 2200 = f

f = 4% × 2200

f = 0.04 × 2200

f = 88

==>Converting £f to $ = g

If £1 = $1.5,

£88 = $g

1 × g = 1.5 × 88

g = $132

==> Converting \frac{g}{400} into % = h%

h = 132÷400 ×100

h = 0.33 × 100

h = 33%

==> √(h + 3) = i

i = √(33 + 3)

i = √36

i = 6

==> i × (3 + 2) = j

j = 6 × (3 + 2)

j = 6 × 5

j = 30

==> j% of 70 = k

k = j% × 70

k = 30% × 70

k = 0.3 × 70

k = 21

==> If k bottles = $63, 30 bottles = $l

21 bottles = $63

30 bottles = $l

21 × l = 63 × 30

21l = 1,890

l = 1,890/21

l = $90

==>If Tim and Mike (m) shares $90 in the ratio 3:2, Mike (m) would receive thus:

⅖ × $90 = m

m = 0.4 × 90

m = $36

==> √m + m = n

n = √36 + 36

n = 6 + 36

n = 42

==>Converting n% to fraction = o

Thus, o = 42/100

o = 21/50

==> o of 250 = p

p = 21/50 × 250

p = (21 × 250)/50

p = 21 × 5

p = 105

==> expressing p as a product of its primes i.e. p = 3 × 5 × q

105 = 3 × 5 × 7

Therefore, q = 7

==> Given a rectangle with dimensions of q cm and r cm, with an area of 56cm². Let's find r.

Area of rectangle = length × width = q × r

Area = 56 cm²

q = 7 cm

r = ?

56 = 7 × r

56/7 = r

8 = r

r = 8 cm

==> r × 0.3 = s

s = 8 × 0.3

s = 2.4

==> s ÷ 0.6 = t

t = 2.4 ÷ 0.6

t = 4

==> If t is in meters, converting t to cm will give us u

Since 1m = 100cm

4m = u cm

1 × u = 100 × 4

u = 400cm

==> Vikki (v) and John shares $u in the ratio 7:3. Thus, Vikki (v) would receive the following:

v = ⁷/10 × $400

v = 0.7 × 400

v = $280

8 0
3 years ago
A fashion designer makes and sells hats. The material for each hat cost $5.50. The Hats sell for $12.50 each. The designer spend
labwork [276]

The designer must sell 200 hats for breaking even.

Step-by-step explanation:

Given,

Cost for material for each hat = $5.50

Selling price of each hat = $12.50

Cost spend on advertising = $1400

Let,

x represents the number of hats.

Revenue = 12.50x

Costs = 5.50x+1400

For breaking even,

Revenue = Cost

12.50x=5.50x+1400\\12.50x-5.50x=1400\\7x=1400

Dividing both sides by 7

\frac{7x}{7}=\frac{1400}{7}\\x=200

The designer must sell 200 hats for breaking even.

Keywords: addition, division

Learn more about division at:

  • brainly.com/question/916181
  • brainly.com/question/9136949

#LearnwithBrainly

7 0
3 years ago
There are three local factories that produce radios. Each radio produced at factory A is defective withprobability .02, each one
diamong [38]

Answer:

The probability is 0.02667

Step-by-step explanation:

Let's call D1 the event that the first radio is defective and D2 the event that the second radio is defective.

So, if we select both radios any factory, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1) = P(D2∩D1)/P(D1)

Taking into account that 0.02 is the probability that a radio produced at factory A is defective, P(D2/D1) for factory A is:

P(D2/D1)_A=\frac{0.02*0.02}{0.02} =0.02

At the same way, if both radios are from factory B, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)_B=\frac{0.01*0.01}{0.01} =0.01

Finally, if both radios are from factory C, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)_C=\frac{0.05*0.05}{0.05} =0.05

So, if the radios are equally likely to have been any factory, the probability to select both radios from any of the factories A, B or C are respectively:

P(A)=1/3

P(B)=1/3

P(C)=1/3

Then, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)=P(A)P(D2/D1)_A+P(B)P(D2/D1)_B+P(C)P(D2/D1)_C

P(D2/D1) = (1/3)*(0.02) + (1/3)*(0.01) + (1/3)*(0.05)

P(D2/D1) = 0.02667

6 0
4 years ago
First answer gets brain
Alex787 [66]
3 \frac{4}{7}m =8 \frac{1}{3} \\ \\\frac{25}{7}m=\frac{25}{3} \\  \\ m= \frac{25}{3}: \frac{25}{7}= \frac{25}{3}* \frac{7}{25}= \frac{7}{3}=2 \frac{1}{3}
4 0
3 years ago
Read 2 more answers
55 is 20% of what numeber
kolbaska11 [484]
The answer is 275. hope it helps :)
4 0
2 years ago
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