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weeeeeb [17]
3 years ago
5

A sandwich costs $0.75 more than a container of milk. A customer buys 4 sandwiches and 4 containers of milk. The customer pays $

7.00. What is the cost of a sandwich?
Mathematics
2 answers:
Iteru [2.4K]3 years ago
8 0
Let x be the cost of a sandwich

7 = 4x + 4 (x-0.75)
7 = 4x + 4x - 3
10 = 8x
8x = 10
x = 10/8
x = 1.25
A sandwich is $1.25
BigorU [14]3 years ago
7 0

Answer : The cost of sandwich is, $1.25

Step-by-step explanation :

Let the cost of sandwich be 'x' and the cost of container of milk be, 'y'

A sandwich costs $0.75 more than a container of milk. The equation will be:

x=0.75+y       .............(1)

A customer buys 4 sandwiches and 4 containers of milk. The customer pays $7.00. The equation will be:

4x+4y=7.00     ..............(2)

Now substitute the value of 'x' from equation 1 to equation 2, we get the value  of 'y'.

4x+4y=7.00

4(0.75+y)+4y=7.00

3+4y+4y=7.00

3+8y=7.00

8y=7.00-3

8y=4.00

y=\frac{4.00}{8}

y=0.5

Now put the value of 'y' in equation 1, we get the value of 'x'.

x=0.75+y

x=0.75+0.5

x=1.25

The cost of sandwich = x = $1.25

The cost of container of milk = y = $0.5

Thus, the cost of sandwich is, $1.25

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Step-by-step explanation:

4x-5=2\left(2x+1\right)

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larisa86 [58]

Answer:

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Step-by-step explanation:

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12-[20-2(6^2\div3\times2^2)]

Recall the order of operations or PEMDAS:

P: Operations within parentheses must be done first. On a side note, do parentheses before brackets.

E: Within the parentheses, if exponents are present, do them before all other operations.

M/D: Multiplication and division next, whichever comes first.

A/S: Addition and subtraction next, whichever comes first.

(Note: This is how the order of operations is traditionally taught and how it was to me. If this is different for you, I do apologize. However, the answer should be the same.)

Thus, we should do the operations inside the parentheses first. Therefore:

12-[20-2(6^2\div3\times2^2)]

The parentheses is:

(6^2\div3\times2^2)

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Therefore, the original equation is now:

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=12-[20-96]

Subtract with the brackets:

=12-[-76]

Two negatives make a positive. Add:

=12+76=88

Therefore:

12-[20-2(6^2\div3\times2^2)]=88

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