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mina [271]
3 years ago
15

Today, the population of Canyon Falls is 22,500 and the population of Swift Creek is 15,200. The population of Canyon Falls is d

ecreasing at the rate of 740 people each year while the population of Swift Creek is increasing at the rate of 1,500 people each year. Assuming these rates continue into the future, in how many years from today will the population of Swift Creek equal twice the population of Canyon Falls?
Mathematics
1 answer:
deff fn [24]3 years ago
7 0

Answer:

  10 years

Step-by-step explanation:

Let c and s represent the populations of Canyon Falls and Swift Creek, respectively. For time t in years, the respective populations are ...

  c = 22500 -740t

  s = 15200 +1500t

We want to find t when s = 2c.

  s = 2c

  15200 +1500t = 2(22500 -740t)

  2980t = 29800 . . . . . add 1480-15200, simplify

  29800/2980 = t = 10 . . . . divide by the coefficient of t

The population of Swift Creek will be double that of Canyon Falls in 10 years.

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3 years ago
Read 2 more answers
Y=− 2 x + 7 ; y = 5 x − 7
Verdich [7]
Do you need to solve for x?
As the both equal y, they must both equal each other so
-2x+7=5x-7
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3 years ago
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saul85 [17]

Answer:

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For surface area, the equation is 6a^2

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3 years ago
George is shooting free throws before basketball practice. He makes 18 out of the 20 shots he attempts. How many shots would you
Marysya12 [62]

Answer: 90

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Another way to solve it is note that 100 is 20*5, so 18*5 is 90, which is also our answer.

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