Answer:
Explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo.
Given:
- Cost $71 per linear foot
- Budge $34080 for those walls
Let X is the the length
Let Y is the width
From the photo, we can see that
(4X + 6Y)*71 = 34080
<=> (4X + 6Y) = 480
<=> Y = 80 - 
X
The are of the rectangular industrial warehouse:
A(X) = 3Y*X
<=> A(X) = 3(80 - X )X
<=>A(X) = (240-2X)X = 240X - 
So A'(X) = 240 - 4X
Let A'(X) = 0, we have:
240 - 4X = 0
<=> X = 60
=> Y =(80 - X ) = 80 - *60 = 40
So the dimension to maximize total area is: 60 in length and 40 in width
Answer:
$222,450
Explanation:
Computation of annual income statement for Kvass Inc. is shown below
Sales revenue
$4,887,000
Less:
Selling and admn expenses
($1,052,000)
Other expenses
($249,300)
Advertising and promotion expenses
($553,350)
Salaries and wages expenses
($2,527,800)
Income tax expenses
($167,350)
Interest expense
($114,750)
Net income
$222,450
The answer is ATM fee in the amount of $2.75 or C.
HOPE THIS HELPS YOU
Answer:
this would cause total costs to Increase and the break-even quantity to Increase.
Explanation:
Total Cost is the Sum of All Manufacturing and Non-Manufacturing Cost of a product.
Advertising expense before adjustments are at $500. The cost of advertising does not vary with the sales quantities therefore this is a fixed cost.
Therefore an Increase in the advertising expense causes an increase in Total cost figure.
Break even quantity is a function of Fixed Costs divided by Contribution per unit.The break even quantity will definitely change. By increasing the fixed costs (<em>Advertising Expense</em>), the Break even quantity will increase.
