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3 years ago

A restaurant makes pizzas with 6-inch diameters ad 12-inch diameters. Which of the following statement is true?

Mathematics

1 answer:

a_sh-v [17]3 years ago

4 0

Answer:

The correct option is c: the area of the 6-inch pizza is 1/4 the area of the 12-inch pizza.

Step-by-step explanation:

The area (A) of each pizza is given by:

$A = \pi r^{2}$

Where:

r: is the radius

For the 12-inch pizza we have:

$A_{12} = \pi (\frac{12 inch}{2})^{2} = 113.1 inch$

And for the 6-inch pizza we have:

$A_{6} = \pi (\frac{6 inch}{2})^{2} = 28.3 inch$

The ratio between A₆ and A₁₂ is:

$\frac{A_{6}}{A_{12}} = \frac{28.3 inch}{113.1 inch} = 0.25 = \frac{1}{4}$

Hence:

$A_{6} = \frac{A_{12}}{4}$

Therefore, the correct option is c: the area of the 6-inch pizza is 1/4 the area of the 12-inch pizza.

I hope it helps you!

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2 years ago

Please solve this, will rate 5 stars and mark as STAR!

Nina [5.8K]

Answer:

$\boxed{5 \cdot \sqrt{2} \cdot \sqrt[6]{5} }$

Step-by-step explanation:

$\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}$

$\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}$

$\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$250=2 \cdot 5^3$

$\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5 \sqrt[3]{2}$

Once

$\sqrt[6]{2} \cdot \sqrt[6]{5} = \sqrt[6]{10}$

We have

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5}$

We can proceed considering the common base of exponentials

$\sqrt[3]{2} \cdot \sqrt[6]{2} = 2^{\frac{1}{3}} \cdot 2^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}$

Therefore,

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2} \cdot \sqrt[6]{5}$

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3 years ago

Please help, photo attached.

steposvetlana [31]

The zeroes of the polynomial functions are as follows:

For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1

<h3>What are the zeroes of a polynomial?</h3>

The zeroes of a polynomial are the vales of the variable which makes the value of the polynomial to be zero.

The polynomials are given as follows:

f(x) = 2x(x - 3)(2 - x)

f(x) = 2(x - 3)²(x + 3)(x + 1)

f(x) = x³(x + 2)(x - 1)

For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2

For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1

For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1

In conclusion, the zeroes of a polynomial will make the value of the polynomial function to be zero.

Learn more about polynomials at: brainly.com/question/2833285

#SPJ1

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1 year ago

The point R is halfway between the integers on the number line below and represents the number ____. (Use the hyphen for negativ

PSYCHO15rus [73]

I guess ur just gunna have to bear with whatever until we have a multiple choice answer selection.

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3 years ago

Elliot wrote a computer program that randomly generates a number from 2 to 10. If he runs the program twice, what is the probabi

Vikentia [17]

Answer:

StartFraction 16 over 81 EndFraction

Step-by-step explanation:

There are 4 prime numbers from 2 to 10 (2, 3, 5, 7) and 9 numbers from 2 - 10. Total possibilities: 9 * 9 = 81

Prime possibilities: 4 * 4 = 16

Therefore the answer is 16/81 or StartFraction 16 over 81 EndFraction

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3 years ago

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