3 years ago

What is the slope-intercept form of the equation for the line?

Mathematics

1 answer:

mart [117]3 years ago

8 0

Answer:

(-4, 2) and (4, -5)

m = (-5 - 2)/(4 - (-4)) = -7/8

y = -7/8 * (x - (-4)) + 2

y = -7/8 * (x + 4) + 2

y = -7/8 * x - 3/2

You might be interested in

Can someone please help

Flura [38]

Answer:

b 120 cm

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

There are 535 students going on a trip each bus holds 73 students how many buses will I need

Dahasolnce [82]

8 buses is what you need

5 0

4 years ago

Read 2 more answers

2/9 of Mrs. Hanak's 18 students are Minton walkers. How many students dismiss as Minton walkers?

Alex

Answer:

2*2=4, 9*2=18, so 2/9 = 4/18, 4 students are Minton walkers.

Step-by-step explanation:

4 0

3 years ago

Write the quadratic function in standard form.<br> f(x) = -x2 + 2x + 4<br> f(x) =

goldenfox [79]

Answer:

$f(x)=-1(x-2)^2+8$

Step-by-step explanation:

Given:

The quadratic function is given as:

$f(x)=-x^2+2x+4$

The standard form of a quadratic function is given as:

$f(x)=a(x-h)^2+k$ , where, 'a', 'h' and 'k' are real numbers.

Now, in order to convert the given function to standard form, we use completing by square method.

$-x^2+2x=-(x^2-2x)=-[(x-2)^2-2^2]=-[(x-2)^2-4]=-(x-2)^2+4$

Now, $f(x)=-x^2+2x+4$ can be rewritten as:

$f(x)=-(x-2)^2+4+4\\f(x)=-1(x-2)^2+8$

Therefore, the standard form of the function is:

$f(x)=-1(x-2)^2+8$

7 0

3 years ago

I need help with this question help me

vekshin1

Fourth root (3/2x)
= [fourth root {3*(2x)^3} / {2x * (2x)^3}]
= [fourth root (3*8x^3}) /(2x)^4]
= [fourth root (24x^3)] / 2x

answer is B. second one

7 0

3 years ago