Vibin fjn no longer in the hospital room for the first place and the only thing i could have is the one who is not working with
C+d=14
c-6=d
then you will plug c+6 in the first equation and you will get:
c+c-6=14
then you get
2c=20
c=10, so the cat is ten years old
the cat is 6 years older than the dog, so the dog is 4 years old
hope that helps :)
Use the first and lay set of x,y values.
Rate of change is change in y/ change in x:
7-10 / 5- -1 = -3/6 = -1/2
The answer is A.-1/2
(-3)(7^2)-7+2
(-3)(49)-7+2
-147-7+2
-154+2
-152
ANSWER:
-152
Answer:
a. 8
b. 2, 3, 4
Step-by-step explanation:
We have to:
Pedro's age = 14 years
Elisa's age = 3 years
The years to elapse = x
Pedro's age = 14 + x
Elisa's age = 3 + x
14 + x = 2 * (3 + x)
14 + x = 6 + 2 * x
14 - 6 = 2 * x - x
x = 8
Eight years must pass before Pedro's age is twice Elisa's
Now the second question:
Let x be the smallest number
Let x + 1 be the consecutive number
Let x + 2 be the consecutive number
x + (x + 1) + (x + 2) = 2 * (x + 2) +1
x + x +1 + x + 2 = 2 * x + 4 + 1
3 * x +3 = 2 * x + 5
3 * x -2 * x = 5 - 3
x = 2
So:
x = 2
x + 1 = 2 + 1 = 3
x + 2 = 2 + 2 = 4
Therefore the numbers are 2, 3, 4 are consecutive and equality is true