Let 
. Then
lies in the second quadrant, so
So we have
and the fourth roots of are
where 
. In particular, they are
Answer:
- 10.5cm,20.8cm,23.3cm — yes
- 6cm, 22.9cm,20.1cm — no
Step-by-step explanation:
If the sides form a right triangle, the sum of the squares of the shorter two sides will equal the square of the longest side.
1. 10.5^2 + 20.8^2 = 23.3^2 . . . . . true algebraic statement; right triangle
__
2. 6^2 +20.1^2 = 440.01 ≠ 22.9^2 = 524.41 . . . . . this is an obtuse triangle
I think answer should be d. Please give me brainlest let me know if it’s correct or not okay thanks bye bye
Answer:
? = 57
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
cos ? = adj/ hyp
cos ? = 14/26
Taking the inverse cos of each side
cos ^-1 ( cos ?) = cos ^-1 ( 14/26)
? = 57.42102961
To the nearest degree
? = 57
Answer:
The answer to your question is
sin Ф = 0.731 and sinФ = -0.731; cos Ф 0.682 and cos Ф = -0.682
Step-by-step explanation:
tan Ф = 1.072, 0 < Ф < 2 π, tan Ф is positive, find the solution in the first and third quadrangle.
- tan Ф = opposite side / adjacent side
- 1.072 / 1 = opposite side / adjacent side
- opposite side = 1.072 and adjacent side = 1
Calculate hypotenuse
c² = a² + b²
c² = 1.072² + 1²
c² = 2.149
hypotenuse = c = 1.466
First quadrangle
sin Ф = 1.072 / 1.466 = 0.731
cos Ф = 1 / 1.466 = 0.682
Third quadrangle
sin Ф = -1.072 / 1.466 = -0.731
cos Ф = -1 / 1.466 = -0.682
