Prove that ΔADB∼ΔADE by writing a proportion which solves for the Pythagorean Theorem.

Mathematics

2 answers:

Cloud [144]3 years ago

6 0

Answer:

B) AD/DE = BD/AD

Step-by-step explanation:

joja [24]3 years ago

6 0

Answer:

The answer is B. Hope this helps

Step-by-step explanation:

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A jeweler is making a triangular pendant. He has two sides of length 23 mm and 31 mm. What are the

denis-greek [22]

Answer:

38.60mm

Step-by-step explanation:

Step one:

Given data

We are given that the dimension of the triangles are length 23 mm and 31 mm

Let us assume that the triangle is a right angle triangle

Step two:

Applying the Pythagoras theorem we can find the third as

$z^2= x^2+y^2\\\\z^2= 31^2+23^2\\\\z^2= 961+529\\\\z^2= 1490\\\\$

square both sides

z= √ 1490

z= 38.60mm

Hence a possible dimension of the third side is 38.60mm

3 0

3 years ago

What number would you add to the equation below to complete the square?x2 + 4x = 0?

julia-pushkina [17]

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Equation
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x² + 4x = 0

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Add a constant
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x² + 4x + (4/2)² - (4/2)² = 0 ← Add 2² to form perfect square

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Evaluate bracket
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x² + 4x + 2² - 2² = 0

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Form the perfect square
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(x + 2)² = 4

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Square root both sides
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(x+2) = $\pm$ √4

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Evaluate the square root
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(x+2) = $\pm$ 2

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Solve x
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x = 2 - 2 or x = -2 - 2

x = 0 or -4

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Answer: The constant to add is 4 and the value of x = 0 or -4
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7 0

4 years ago

Solve for x. Round to the nearest tenth of a degree, if necessary.

MissTica

Answer:

x ≈ 54.8°

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan x = $\frac{opposite}{adjacent}$ = $\frac{PQ}{QR}$ = $\frac{7.1}{5}$ , then