Will give BRAINLIEST for correct answer

5 pounds of rice at a store cost $6.50 use the ray tool to graph the cost C, vs pounds of rice

Kobotan [32]

Given that 5 pounds of rice at a store cost $6.50.

Then 1 pounds of rice at a store cost = $6.50/5= $1.3

So the equation for the cost can be written as:

C=1.3P just like we write equation y=mx

Now we have to graph the cost C, vs pounds of rice.

Variable for Pounds of rice is not given so let it be "P"

So let's make a table for number of pounds (P) and cost (C) the we can graph the points from that table to get the final graph.

Attached graph is the final graph.

4 0

3 years ago

Which sets of side lengths could form a triangle? Choose all that apply.

Svetlanka [38]

Answer:

4, 6, 9 and 5, 5, 9

4 0

3 years ago

Jeremey performs the same operations on four values of x. He records each resulting y-value in a table, as shown below. Which eq

Anestetic [448]

Answer:

Y=4x-3

Explanation: If we look 2 = 5 We can do 4(2)= 8 -3 = 5 So that the answer and 4(4)= 16-3 = 13 so these are the Y so this is the answer!

6 0

3 years ago

Match the phenomenal expression on the left with the simplified version on the right

nalin [4]

Given the polynomial expression:

(y + 5)²

(y - 5)(y + 5)

Let's simplify each of the given expression:

a.) (y + 5)²

The given equation is a factor of a perfect square trinomial. For this type of expression, the following is the formula for expanding it.

$\text{ (a+b)}^2\text{ = }a^2\text{ + 2ab + }b^2$

We get,

$\mleft(y+5\mright)^2=(y)^2+2(y)(5)+(5)^2$ $(y+5)^2=y^2+10y+25$

b.) (y - 5)(y + 5)

To be able to simplify the following expression. We will be using the formula for the difference of two squares.

$(a+b)(a-b)=a^2-b^2$

We get,

$\mleft(y-5\mright)\mleft(y+5\mright)=(y)^2-(5)^2$ $(y-5)(y+5)=y^2-25^{}$

8 0

1 year ago

In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s

Oksi-84 [34.3K]

Answer:

a) $\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

b) From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

c) $P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

$P(Z\geq2.070)=1-P(Z$

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

$\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4$

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

$\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

Part c

For this case we want this probability:

$P(\bar X \geq 285)$

And we can use the z score defined as:

$z=\frac{\bar x -\mu}{\sigma_{\bar x}}$

And using this we got:

$P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

And using a calculator, excel or the normal standard table we have that:

$P(Z\geq2.070)=1-P(Z$

8 0

3 years ago