I think it would be (x+7)/7
Answer:
The ordered pair that describes the location of K' is (5,4).
Step-by-step explanation:
Reflection over the x-axis:
When a point is reflected over the x-axis, it's x-coordinate stays the same, while the signal of the y-coordinate is changed. So
(x,y) -> (x,-y)
In this question:
Point K(5,-4)
Reflection over the x-axis:
(5,-4) -> (5,-(-4)) -> (5,4)
The ordered pair that describes the location of K' is (5,4).
Answer:
1
Step-by-step explanation:
0×0=0
1-0=1
when we put into this equation
0+1÷1
1÷1=1
so, 0+1=1
hopefully it works
Answer:
y" - 8y' + 15y = 0
2nd order Homogeneous DE.
Solving Quadratically
k² - 8k + 15 = 0
k= 5 or k= 3.
Two real and Unequal roots.
y= Ae^5x + Be^3x.
2√5................................
