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Bezzdna [24]
3 years ago
11

The area of a rectangle is equal to its length times its width. If the area of a rectangle is 4x + 20, which option(s) could be

the length and width of that rectangle? Select all that apply.
Mathematics
1 answer:
Pavel [41]3 years ago
5 0

Answer:

length = 4

Breadth = x+5

Step-by-step explanation:

Area = length x breadth

Area = 4x+20

In order to get the length and the breadth we have to use factorization on the equation 4x+20

Such that area = 4(x+5)

Then the length = 4

Breadth = x+5

And if we multiply the length and breadth, we will get the original equation

4(x+5) = 4x+20

Thank you!

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What is the equation, in standard form, of a parabola that models the values in the table?
love history [14]

Answer:

<u>Y=4x^2+3x-6</u>

Step-by-step explanation:

For the standard form equation to model the values in the table, each value of x in the table should give the matching the y value when substituted into the equation. We will test each equation:

<u>Y=3x^2+4x-6 for (-2,4)</u>

Y=3(-2)^2+4(-2)-6=3(4)+-8-6=12+-8-6=-2\\

This does not give 4 as the answer and is not a solution.

<u>Y=4x^2+3x-6 for (-2,4)</u>

Y=4(-2)^2+3(-2)-6=4(4)+-6-6=16+-6-6=-4\\

This does give 4 as the answer and is a possible solution.

<u>Y=4x^2-3x-6 for (-2,4)</u>

Y=4(-2)^2-3(-2)-6=4(4)+6-6=16+6-6=16\\

This does not give 4 as the answer and is not a solution.

<u>Y=-4x^2-3x-6 for (-2,4)</u>

Y=-4(-2)^2-3(-2)-6=-4(4)+6-6=-16+6-6=-16\\

This does not give 4 as the answer and is not a solution.

The only possible solution is <u>Y=4x^2+3x-6</u>

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Answer:

See explanation

Step-by-step explanation:

Q11.     Statement            Reason

1. \overrightarrow {MO} bisects \angle PMN     Given

2. \angle PMO\cong \angle NMO        Definition of angle bisector

3. \overline{MO}\cong \overline{MO}                   Reflexive property

4.  \overrightarrow {OM} bisects \angle PON    Given

5. \angle POM\cong \angle NOM        Definition of angle bisector

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Q13.

1. Consider triangles ACB and DCE. In these triangles,

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2. congruent triangles have congruent corresponding sides, so

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